Answer:
9.39 m/s
Explanation:
Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.
Assume the up direction is positive and the down direction is negative.
- v₀ = 0 m/s
- a = -9.8 m/s²
- Δy = -50 m
- t = ?
Find the constant acceleration equation that contains these four variables.
Substitute known values into this equation.
Multiply and simplify.
Divide both sides of the equation by -4.9.
Square root both sides of the equation.
Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.
List out known variables in the x-direction.
- v₀ = ?
- t = 3.194382825 s
- a = 0 m/s²
- Δx = 30 m
Find the constant acceleration equation that contains these four variables.
Substitute known values into the equation.
- 30 = (v₀ · 3.194382825) + 1/2(0)(3.194382825)²
Multiply and simplify.
Divide both sides of the equation by 3.194382825.
The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.
The giant squid, which has an estimated weight of 0.37 tons dispersed across a length of 40 feet, is the biggest invertebrate. It will weigh 3,628.4605 newtons.
<h3>What is weight?</h3>
The weight of matter is found as the product of the mass and the gravitational acceleration.
Unit conversion;
1 ton = 9806.65 N
0.37 tons = 0.37 × 9806.65 N
0.37 tons = 3,628.4605 N
Hence its weight in newtons will be 3,628.4605.
To learn more about the weight refer;
brainly.com/question/10069252
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Speed of the black Mamba = 18 km/h = 5m/s
now the distance that black mamba cover to catch prey
Now it returns to its hide in 12 s
so average speed of return is given as
Part b)
For the whole trip we know that displacement of the mamba is zero
so average velocity of whole trip will be zero
Part c)
For average speed we know that total distance of the black mamba
d = 12.5 + 12.5 = 25 m
total time taken = 2.5 + 12 = 14.5 s
now average speed is given as
Regular reflection is a reflection such that the the angle of reflection of the light is equal to the angle of incidence and it is on the opposite of the normal to the point of incidence. In a regular reflection the incident ray, the reflected ray and the normal to the reflection all lie in the same plane. Regular reflection happens if the reflection surface is very smooth.