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Darina [25.2K]
2 years ago
11

The apparent brightness of stars in general tells us nothing about their distances; we cannot assume that the dimmer stars are f

arther away. In order for the apparent brightness of a star to be a good indicator of its distance, all the stars would have to be:__________.
a. at the same distance
b. the same composition
c. the same luminosity
d. by themselves instead of in binary or double-star systems
e. a lot farther away than they presently are
Physics
1 answer:
antoniya [11.8K]2 years ago
3 0
The answer is have the same luminosity
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In the demolition of an old building, a 1,300 kg wrecking ball hits the building at 1.07 m/s2. Calculate the amount of force at
Y_Kistochka [10]

Answer: F = 1391 N

Explanation:

The information given to you are:

Mass M = 1300 kg

Acceleration a = 1.07 m/s^2

The magnitude of the force striking the building will be

F = ma

Where

F = force

Substitute mass M and acceleration a into the formula

F = 1300 × 1.07

F = 1391 N

Therefore, the wrecking ball strikes the building with a force of 1391 N

3 0
3 years ago
Are you like you are because of your genes or because of your environment?
meriva
You are who you are because of your enviorment. It depends if your in a healthy environment or a toxic one which changes your act. (Hope this helps)
5 0
3 years ago
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Red light of wavelength 630 nm passes through two slits and then onto a screen that is 1.4 m from the slits. The center of the 3
VARVARA [1.3K]

Answer:

Part a)

f = 4.76 \times 10^{14} Hz

Part b)

d = 3.48 \times 10^{-4} m

Part c)

\theta = 0.311 degree

Explanation:

Part a)

As we know that the speed of light is given as

c = 3 \times 10^8 m/s

\lambda = 630 nm

now the frequency of the light is given as

f = \frac{c}{\lambda}

so we have

f = \frac{3 \times 10^8}{630 \times 10^{-9}}

f = 4.76 \times 10^{14} Hz

Part b)

Position of Nth maximum intensity on the screen is given as

y_n = \frac{n\lambda L}{d}

so here we know for 3rd order maximum intensity

y_3 = 0.76 cm

n = 3

L = 1.4 m

0.76 \times 10^{-2} = \frac{3(630 \times 10^{-9})(1.4)}{d}

d = 3.48 \times 10^{-4} m

Part c)

angle of third order maximum is given as

d sin\theta = 3 \lambda

3.48 \times 10^{-4} sin\theta = 3(630 \times 10^{-9})

\theta = 0.311 degree

8 0
3 years ago
A fast pitch softball player does a "windmill" pitch moving her hand through a vertical circular arc to pitch a ball at 70mph. T
uysha [10]

Answer:

Explanation:

The hand throwing ball moves on a circular path having radius r = .55 m

mass of ball m = .19 kg

velocity v = 70 mph

= 70 x 1600 / 60 x 60

= 31.11 m /s

centripetal force

= mv² / r

= .19 x 31.11² / .55

= 334.34 N

8 0
3 years ago
……………………………………………………………..?
TEA [102]

Answer:

last is the answer.

increase the voltage in order to send energy faster.

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