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Pavlova-9 [17]
3 years ago
11

The table below compares the cost of living in Philadelphia

Physics
2 answers:
Feliz [49]3 years ago
6 0
It should be A sorry if I’m wrong
valina [46]3 years ago
6 0

Answer:

$3.03 / $2.75

Explanation:

APEX

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Which of the following would decrease the resistance to the flow of an electric current through a body?
Nookie1986 [14]
R = ρ L/A. R= resistance, ρ= resistivity, L= length of the conductor. A = area of the conductor. Resistance is directly proportional to the length of the conductor. So if length of the conductor is decreased, resistance will also decrease. Hence A is the correct option
3 0
3 years ago
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Suppose the electrostatic force between two electrons is F. What is the electrostatic force between an electron and a proton
mars1129 [50]

Answer:

D. −F

Explanation:

the rest of the answers are

2/3F

The force is represented as a positive quantity and is repulsive.

Electrostatic force is inversely proportional to the square of the distance.

The direction of the force changes, and the magnitude of the force quadruples.

hope this helps sorry if i was too late! :)

8 0
3 years ago
Imagine an isolated positive point charge Q (many times larger than the charge on a single proton). There is a charged particle
egoroff_w [7]

Answer:

Explanation:

The magnitude of the electric force on this charged particle A depends upon the following

5. the distance between the point charge Q and the charged particle A

8. the amount of the charge on the point charge Q

9. the magnitude of charge on the charged particle A

7 0
3 years ago
What is used to measure the speed of a moving vehicle along the road​
Romashka [77]

Answer:

Speedometer

Explanation:

Speedometer

8 0
3 years ago
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As mentioned in the text, the tangent line to a smooth curve r(t) = ƒ(t)i + g(t)j + h(t)k at t = t0 is the line that passes thro
LiRa [457]

Answer:

x = t

y = \frac{1}{3}t

z =t

Explanation:

Given

r(t) = f(t)i + g(t)j + h(t)k at t = 0

Point: (f(t0), g(t0), h(t0))

r(t) = ln\ t_i + \frac{t-1}{t+2}j + t\ ln\ tk, t0 = 1 -- Missing Information

Required

Determine the parametric equations

r(t) = ln\ ti + \frac{t-1}{t+2}j + t\ ln\ tk

Differentiate with respect to t

r'(t) = \frac{1}{t}i +\frac{3}{(t+2)^2}j + (ln\ t + 1)k

Let t = 1 (i.e t0 = 1)

r'(1) = \frac{1}{1}i +\frac{3}{(1+2)^2}j + (ln\ 1 + 1)k

r'(1) = i +\frac{3}{3^2}j + (0 + 1)k

r'(1) = i +\frac{3}{9}j + (1)k

r'(1) = i +\frac{1}{3}j + (1)k

r'(1) = i +\frac{1}{3}j + k

To solve for x, y and z, we make use of:

r(t) = f(t)i + g(t)j + h(t)k

This implies that:

r'(1)t = xi + yj + zk

So, we have:

xi + yj + zk  = (i +\frac{1}{3}j + k)t

xi + yj + zk  = it +\frac{1}{3}jt + kt

By comparison:

xi = it

Divide by i

x = t

yj = \frac{1}{3}jt

Divide by j

y = \frac{1}{3}t

zk = kt

Divide by k

z = t

Hence, the parametric equations are:

x = t

y = \frac{1}{3}t

z =t

3 0
3 years ago
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