Answer:
Solution given:
3(5x+8)
distribute
15x+8*3
<u>1</u><u>5</u><u>x</u><u>+</u><u>2</u><u>4</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
<h2>
Explanation:</h2><h2>
</h2>
Hello! Remember you have to write complete questions in order to get good and exact answers. Here you forgot to write the relation so I could help you providing my own relation.
Remember that for any relation, we have a set
that matches the the domain (also called the set of inputs) of the function and the set
that contains the range (also called the set of outputs).
Suppose our relation is:

So the x-values represents the set A and the y-values the set B. Therefore, by evaluating the x-values into our relation we get:

So in this context, the correct option is:
B) (-9,-8, -7, -6, -5}