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djverab [1.8K]
3 years ago
13

Four buses were filled with children and 20 children rode in cars for a field trip. If each bus can hold 58 children, how many w

ent on the field trip?
Mathematics
1 answer:
Wewaii [24]3 years ago
8 0
The correct answer to your question is 252 children
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bag contains 15 marbles numbered from 1 to 15. Two marbles are selected from the bag at the same time. Let event E = the two num
lbvjy [14]
The numbers DO differ by 10 if they are

- 1 and 11
- 2 and 12
- 3 and 13
- 4 and 14
- 5 and 15

Each outcome technically has two ways of occurring, but since we're taking two marbles at a time, that would be the same as saying, for instance, that drawing 1 and 11 is the same as drawing 11 and 1. We only count such an event once.

So the answer is (a) 5.
7 0
3 years ago
Read 2 more answers
If anyone can solve this quickly I will give brainly
Nataly [62]

Answer:

m∠BFE  = 171º

BE = 219º

Step-by-step explanation:

∠BFE is supplementary to ∠EFC

m∠BFE  = 180 - 9

m∠BFE  = 171º

--------------------------

The angle between two chords is equal to half the sum of the intercepted arcs:

∠BFE = (DC + BE)2

171 = (123 + BE)/2

342 = 123 + BE

219º = BE

6 0
3 years ago
(25 points) Can someone please solve this I just need to see how its solved to understand
aleksley [76]

x = total amount of students in 8th Grade.

we know only one-thrid of the class went, so (1/3)x or x/3 went.

we also know 5 coaches went too, and that the total amount of that is 41.

\bf \stackrel{\textit{one third of all students}}{\cfrac{1}{3}x}+\stackrel{\textit{coaches}}{5}=\stackrel{\textit{total}}{41}\implies \cfrac{x}{3}+5=41\implies \cfrac{x}{3}=41-5 \\\\\\ \cfrac{x}{3}=36\implies x=3(36)\implies x=108

now, to verify, well, what do you get for (108/3) + 5?

4 0
3 years ago
I need help. this is the problem x^2/3+10=7x^1/3
Arlecino [84]

\it x^{\frac{2}{3}}+10=7x^{\frac{1}{3}} \Leftrightarrow  (x^{\frac{1}{3}})^2-7x^{\frac{1}
  {3}} +10=0 
\\\;\\
We\ note\ x^{\frac{1}{3}} =t \ \ and \ the \ equation \ will \ be:
\\\;\\
t^2-7t+10 = 0 \Leftrightarrow t^2 -2t-5t+10=0 \Leftrightarrow t(t-2) -5(t-2)=0

\it \Leftrightarrow (t-2)(t-5)=0 
\\\;\\
t-2=0 \Rightarrow t=2 \Rightarrow x^{\frac{1}{3}}=2 \Rightarrow (x^{\frac{1}{3}})^3 =2^3 \Rightarrow x = 8
\\\;\\
t-5=0 \Rightarrow t=5 \Rightarrow x^{\frac{1}{3}}= 5  \Rightarrow (x^{\frac{1}{3}})^3 = 5^3 \Rightarrow x = 125

S = {8; 125}


7 0
4 years ago
The Bailey family is traveling 565.5 miles for a family vacation. If they estimate they can travel 78 miles per hour how many ho
Vinil7 [7]
565.5/78
7.25 miles per hours it will takes 
5 0
4 years ago
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