First let's find out the oxidation number of Fe in K₄[Fe(CN)₆] compound.
The oxidation number of cation, K is +1. Hence, the total charge of the anion, [Fe(CN)₆] is -4. CN has charge has -1. There are 6 CN in anion. Let's assume the oxidation number of Fe is 'a'.
Sum of the oxidation numbers of each element = Charge of the compound
a + 6 x (-1) = -4
a -6 = -4
a = +2
Hence, oxidation number of Fe in [Fe(CN)₆]⁴⁻ is +2.
Now Fe has the atomic number as 26. Hence, number of electrons in Fe at ground state is 26.
Electron configuration = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶ 4s² = [Ar] 3d⁶ 4s²
When making Fe²⁺, Fe releases 2 electrons. Hence, the number of electrons in Fe²⁺ is 26 - 2 = 24.
Hence, the electron configuration of Fe²⁺ = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶
= [Ar] 3d⁶
Hence, the number of 3d electrons of Fe in K₄[Fe(CN)₆] compound is 6.
Answer:
82.24% percent composition of N and 17.76% percent composition of H .
Explanation:
<h3><u>Answer;</u></h3>
10 ft
<h3><u>Explanation;</u></h3>
The wave base of a wave is the depth at which there is no more perturbation of the medium caused by the wave. The wave base of a wave is determined to be half the wavelength of the wave itself.
Therefore;
Wave base = wavelength/2
= 20 ft/2
<u> = 10 ft</u>
Answer:
X = 5
Explanation:
Total mass here is 1.5g. Now after heating we have a mass of 0.957g Cu. This means heating had caused a loss of 1.5 - 0.957 = 0.543g of water.
Now, we will try to convert this into moles. This can be done by dividing the respective masses by the molar masses. While the mass of water is 18g/mol, the molar mass of CuSO4 is 160g/mol.
The division of the respective masses by the molar masses is thus:
CuSO4 = 0.957/160 = 0.006 moles
H2O = 0.543/18 = 0.03 moles
The ratios of the moles is thus: 0.03/0.006 = 5
Hence, the number of molecules of water of crystallization is 5
This means x = 5
