<span>Ne 3s2 3p2. Thats the answer and i hope it helped!</span>
V1/T1 =V2/T2 (using charles law)
V1=6.00
V2=?
T1=273
T2=273
Making V2 the subject of formula the equation then becomes
V2= V1xT2/T1
6.00x263/273=6.0L
Answer:
3.2 moles
Explanation:
First, we'll begin by writing a balanced equation for the Combustion of methane to produce carbon dioxide. This is illustrated below:
CH4 + 2O2 —> CO2 + 2H2O
From the balanced equation above,
1 mole of methane (CH4) reacted to produced 1 mole of carbon dioxide (CO2).
Therefore, 3.2 moles of methane (CH4) will react to produce 3.2 moles of carbon dioxide (CO2).
From the illustration above, 3.2 moles of methane is needed to produce 3.2 moles of carbon dioxide.
Answer:
0.21 g
Explanation:
The equation of the reaction is;
NaCl(aq) + AgNO3(aq) -----> NaNO3(aq) + AgCl(s)
Number of moles of NaCl= 0.0860 g /58.5 g/mol = 0.00147 moles
Number of moles of AgNO3 = 30/1000 L × 0.050 M = 0.0015 moles
Since the reaction is 1:1, NaCl is the limiting reactant.
1 mole of NaCl yields 1 mole of AgCl
0.00147 moles of NaCl yields 0.00147 moles of AgCl
Mass of precipitate formed = 0.00147 moles of AgCl × 143.32 g/mol
= 0.21 g
Answer:
c ammonium hydroxide nh4oh has higher ph value and its a base
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