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statuscvo [17]
2 years ago
5

_______ properties depend on the concentration of a solute in a solution but not on the identity of the solute.

Chemistry
1 answer:
Grace [21]2 years ago
5 0

This problem is providing us with a statement in which we need to figure out the word fitting in the blank. At the end, after analyzing the information, the word turns out to be colligative as show below:

<h3>Colligative properties.</h3>

In chemistry, colligative properties of solutions account for the behavior of a solution with respect to the pure solvent, to which a solute is added.

Among them, we have boiling point elevation, freezing point depression, vapor pressure lowering and osmotic pressure, which are all affected by the concentration of the solute but not by the identity of the solute.

In such a way, we conclude that the correct word that fits in the blank is colligative as shown below:

"Colligative properties depend on the concentration of a solute in a solution but not on the identity of the solute."

Learn more about colligative properties: brainly.com/question/10323760

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7 0
3 years ago
Please help with this
dlinn [17]

Answer:

A sample of a gas (5.0 mol) at 1.0 atm is expanded at constant temperature from 10 L to 15 L. The final pressure is 0.67 atm.

Step by Step Explanation?

Boyle's law states that in constant temperature the variation volume of gas is inversely proportional to the applied pressure.

The formula is,

P₁ x V₁ = P₂ × V₂

Where,

P₁ is initial pressure = 1 atm

P2 is final pressure = ? (Not Known)

V₁ is initial volume = 10 L

V₂ is final volume = 15 L

Now put the values in the formula,

\begin{gathered}\rm 1\times 10 = P_2\times 15\\\\\rm P_2 = \frac{10}{15\\} \\\\\rm P_2 = 0.67\end{gathered]

Therefore, the answer is 0.67 atm.

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Answer:

Has size and magnitude whereas a scalar quantity has only size

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Find the density of an object that has a mass of 12.69 grams and a volume of 3.5cm3
lutik1710 [3]

Answer:

3.62 g/cm³

Explanation:

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Therefore, do 12.69 divided by 3.5

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Density increases with the temperature, true.
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