Let's find out the gradient (Slope " m ") of line q ;
Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :
Now, plug in the value of gradient ~
here we can clearly observe that, the Area under the curve can easily be represented as :
Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q
You use the area for volume length times width times high
8x4313x2628
Answer:
360 mi/h
Step-by-step explanation:
The speed for the outbound trip was ...
speed = distance/time = (715 mi)/(2 1/6 h) = 330 mi/h
The inbound speed was ...
(715 mi)/(1 5/6 h) = 390 mi/h
The airspeed of the plane is the average of these two ground speeds, so is ...
(330 +390)/2 = 360 . . . . mi/h
Answer:
i think it is. r = -s + 3z could be wrong sorry if it is
-68hen you enter an equation into the calculator, the calculator will begin by expanding (simplifying)
the problem.
