Answer:
24.11
Step-by-step explanation:
2001 ÷ 83
83×2= 166
200-166=34 bring down the 1
341 ÷ 83
83×4= 332
341-332=9 add a decimal and bring down a 0
90÷83
90-83=7 bring down another 0
70÷83=0 brind down another 0 since 70 cannot be divided by 83 and have a whole number
700÷83
83×8=664
700-664=36
right now you have 24.108
round to the nearest tenth
24.11
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.
Using pythagoras theorem,

and

Angle θ is given by

Given that a = 4 units, b = 5 units, and c = 9 units, thus

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.

Given that x is a point on line segment AB, this means that x is a positive number less than 5.
Thus

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
The answer is 0.1538461538 but you round it to the nearest tenth that gives you 0.2
Since Perimeter is Length+ Width, and there are "two lengths" and "two widths", the formula needed here is p=2l+2w. We have the P, so using that, along with knowing that l is 41ft longer than w;
p = 278 , l = w+41
278 = 2l + 2w
278 = 2(w+41) + 2w
We'll use the DISTRIBUTIVE PROPERTY first: 278 = 2w + 82 + 2w
Then we'll COMBINE LIKE TERMS: 278 = 4w + 82
Next we'll subtract 82 from both sides: 196 = 4w
And finally divide both sides by 4:
49 = w
Since the length is w+41 and we now know the width, we can see what the length is: l = w+41 , l = 49 + 41 , l = 90.
Now that we know the length, we can see what the dimensions of the court are:
Perimeter is 278ft
Width is 49ft
And the Length is 90ft.