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Nady [450]
3 years ago
7

Select all the expressions equivalent to:

Mathematics
1 answer:
olchik [2.2K]3 years ago
8 0

Answer:

5(4a + 2b)

10(2a + b)

2(10a + 5b)

Step-by-step explanation:

we are trying to find equations equivalent to (20a + 10b), so distribute

5(4a + 2b) = 20a +10b YES

10(2a + b) = 20a +10b YES

2(10a +5) = 20a + 10 NO

2(10a + 5b) = 20a +10b YES

5(4a - 2b) = 20a - 10b NO

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A city planner designs a park that is a quadrilateral with vertices at J(-1, 1), K (3, 3), L (5, -1), and
Liono4ka [1.6K]

9514 1404 393

Answer:

  83 m

Step-by-step explanation:

The attached diagram shows the lengths of the midlines to be 3.16 and 5.10 units on the coordinate plane. The sum of these is (3.16 +5.10) = 8.26 coordinate plane units. Since each unit on the coordinate plane represents 10 m, the total path length is about ...

  8.26(10 m) = 82.6 m ≈ 83 m

_____

The distance formula will tell you the distances are ...

  AC = √(3² +1²) = √10

  BD = √(5² +1²) = √26

The total path length is about (10 m)(√10 +√26) ≈ 82.61230 m ≈ 83 m.

3 0
3 years ago
Solve the quadratic equation<br> x2-10x+49=4x+1
CaHeK987 [17]

Answer:

x=8 & x=6

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
How many zeros in x^4 + 3x2 + 12
barxatty [35]

Answer:

We know that ,

Number of zeroes in a polynomial = degree of the polynomial

( degree of polynomial = the highest power in the polynomial )

therefore ,

\bold\blue{number \:of \:zeroes \:of\: the \:given} \\\bold\blue{polynomial\: = \:4}

hope helpful~

3 0
2 years ago
What is the solution to the inequality <br> X+ (7 + 2x) &lt;-3x
dolphi86 [110]

Answer:

x \:  <  \:- 1   \frac{1}{6}

Step-by-step explanation:

The given inequality is

x+ (7 + 2x) <-3x

Expand parenthesis to get

x+ 7 + 2x <-3x

Group similar terms

x+ 2x +3x<-7

Combine similar terms

6x<-7

Divide both sides by 6

x \:  <  \:  -  \frac{7}{6}

Rewrite as improper fraction

x \:  <  \:- 1   \frac{1}{6}

3 0
4 years ago
Sue drove her car 253 miles in january, 277 miles in february, and 280 miles in march. if her average mileage for the four month
Ostrovityanka [42]
X= miles driven in April


(253 + 277 + 280 + x)/4= 284
add in parentheses

(810 + x)/4= 284
multiply both sides by 4

810 + x= 1136
subtract 810 from both sides

x= 326 miles


ANSWER: She must drive 326 miles in April to average at least 284 miles January through April.

Hope this helps! :)
5 0
3 years ago
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