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2 years ago

Henry begins a savings account with $500. The savings account accumulates 2.5% annual interest based on the

1 answer:

4 0

After t years, the expression that can be used to represent the money in Andres's account is A = P(1 + r/n)^nt

for t = 3

Answer:

A = $538.45

<h3 /><h3>Compound interest Computation</h3>

Given Data

Principal P = $500

Rate r = 2.5%

Time t = 3 years

A = P + I where

P (principal) = $500.00

I (interest) = $38.45

Calculation Steps:

First, convert R as a percent to r as a decimal

r = R/100

r = 2.5/100

r = 0.025 rate per year,

Then solve the equation for A

A = P(1 + r/n)^nt

A = 500.00(1 + 0.025/1)^(1)(3)

A = 500.00(1 + 0.025)^(3)

A = $538.45

Summary:

The total amount accrued, principal plus interest, with compound interest on a principal of $500.00 at a rate of 2.5% per year compounded 1 times per year over 3 years is $538.45.

Learn more about compound interest here:

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A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

4 years ago

PLZ HELP/......<br> :)<br><br> :?

alexdok [17]

Answer:

3 gallons of diesel weight = <u>22.2 pounds </u>

The constant of variation = <u>7.4</u>

The quantities vary <u>directly</u>

Step-by-step explanation:

Given:

5 gallons of gas weights = 37 pounds

To find

a) the weight of 3 gallons of gas.

b) if the quantities vary directly or inversely.

c) the constant of variation.

Solution:

Applying unitary method to find weight of 3 gallons of gas.

If 5 gallons weight = 37 pounds

Then, 1 gallon will weight = $\frac{37}{5}$ =7.4 pounds

Thus, 3 gallons will weight = $3\times 7.4$ = 22.2 pounds

Listing out the data we have:

1 gallon = 7.4 pounds

3 gallons = 22.2 pounds

5 gallons = 37 pounds

From the data, we find out that as the number of gallons of gas increases the weight of gas also increases. This shows that these quantities are directly proportional to each other.

<em>The unit rate of the quantities is called the constant of variation.</em>

<em>Unit rate: 7.4 pounds per gallon</em>

Thus, the constant of variation = 7.4

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3 years ago

1 17/20 as a fraction in simplest form

rusak2 [61]

Answer:

37/20

Step-by-step explanation:

I hope it helps...

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