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Nady [450]
3 years ago
5

Complete the missing parts of the table for the following function

Mathematics
1 answer:
djyliett [7]3 years ago
8 0

Step-by-step explanation:

equation y = 6^{x}

When x = -1

y = 6^{-1} = \frac{1}{6} (Answer)

When x = 0,

y = 6^{0} = 1 (Answer)

When x = 3,

y = 6^{3} = 216 (Answer)

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The weekly salary of a store manager includes a $30 bonus plus the number of hours the manager works multiplied by the managers
gizmo_the_mogwai [7]

Yes. The situation is defined by a linear function.

<u>Solution:</u>

Given, The weekly salary of a store manager includes a $30 bonus plus the number of hours the manager works multiplied by the managers earnings per hour.  

Is this situation defined by a linear function?

Yes, the above given situation is defined by a linear function.

Now, let us see the linear equation for above situation

Let the number of hours worked by manager be "x", and cost per hour be "c" and total salary be "y"

Then, total salary is given as,

Total salary = $ 30 bonus + number of hours worked \times cost per hour

\rightarrow \mathrm{y}=30+\mathrm{x} \times \mathrm{c}\\\\ \rightarrow \mathrm{y}=\mathrm{c} \mathrm{x}+30

Above equation is a linear equation as "c" is constant ( cost per hour )

Hence, the given situation can be defined by linear function.

5 0
3 years ago
Estimate the area of Alberta in square miles. Show your reasoning
ella [17]

Answer:  About 278,250\ mi^2

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid  can be calcualted with the formula:

A_t=\frac{h}{2}(B+b)

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

 A_r=lw

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

A=\frac{h}{2}(B+b)+lw

Substituting vallues, you get:

A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2

Therefore, the area of of Alberta is about 278,250\ mi^2.

5 0
3 years ago
What is an equation of the line that passes through
lys-0071 [83]

Answer:

B

Step-by-step explanation:

For the perpendicular of an equation you need to flip the fraction and change the sign from positive to negative or if it's negative to positive. 3/2 is changed to -2/3 which when multiplied by -2 gives you 4/3 and 4/3+5/3 is equal to 3.

3 0
3 years ago
A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are
IRINA_888 [86]

Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5 percent of these are defective.

This means that p = 0.05

If two items are randomly selected as they come off the production line, what is the probability that both are defective

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025

0.0025 = 0.25% probability that both are defective

4 0
3 years ago
Help 123456 please help please
uysha [10]
Number 3 is 7

Number 4 is 3

And number 6 is 9

Im sorry I dont know the rest.

I hope this helps.
4 0
3 years ago
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