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2 years ago

Compare the inner planets with the outer planets.

Physics

2 answers:

makvit [3.9K]2 years ago

6 0

<h2>Answer:</h2>

Inner Planets:

- Rocky

- Small

- Only 3 moons total

- Very close to each other (for space)

- Underweight

Outer Planets:

- Gassy oop-

- GIANT

- Over 200 moons total

- VERY far from each other

- Obese

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Good luck foe.

Lb.

Flura [38]2 years ago

6 0

Iyaz

Shawty's like a melody in my head

That I can't keep out

Got me singin' like

Na na na na everyday

It's like my iPod's stuck on replay

Replay-ay-ay-ay

Shawty's like a melody in my head

That I can't keep out

Got me singin' like Na na na na everyday

It's like my iPod's stuck on replay

Replay

Remember the first time we met

You was at the mall wit yo friend

I was scared to approach ya

But then you came closer

Hopin' you would give me a chance

Who would have ever knew

That we would ever be more than friends

We're real worldwide, breakin' all the rules

She like a song played again and again

That girl -

Like somethin' off a poster

That girl -

Is a dime they say

That girl -

Is the gun to my holster

She's runnin' through my mind all day (Ay!)

Shawty's like a melody in my head

That I can't keep out

Got me singin' like Na na na na everyday

It's like my iPod's stuck on replay

Replay-ay-ay-ay

Shawty's like a melody in my head

That I can't keep out

Got me singin' like Na na na na everyday

It's like my iPod's stuck on replay

Replay-ay-ay-ay

See you been all around the globe

Not once did you leave my mind

We talk on the phone, from night til the morn

Girl you really changed my life

Doin' things I never do

I'm in the kitchin cookin' things she likes

We're real worldwide, breakin' all the rules

Someday I wanna make you my wife

That girl -

Like somethin' off a poster

That girl -

Is a dime they say

That girl -

Is the gun to my holster

She's runnin' through my mind all day (Ay!)

Shawty's like a melody in my head

That I can't keep out

Got me singin' like Na na na na everyday

It's like my iPod's stuck on replay

Replay-ay-ay-ay (Whoa)

Shawty's like a melody in my head

That I can't keep out

Got me singin' like Na na na na everyday

It's like my iPod's stuck on replay

Replay-ay-ay-ay

I can be your melody

A girl that could write you a symphony

The one that could fill your fantasies

So come baby girl let's sing with me

Ay!

I can be your melody

A girl that could write you a symphony

The one that could fill your fantasies

So come baby girl let's sing with me

Ay!

Na na na na na na na

Na na na na na na

Shawty got me singin'

Na na na na na na na

Na na na na na na

Now she got me singin'

Shawty's like a melody in my head

That I can't keep out

Got me singin' like Na na na na everyday

It's like my iPod's stuck on replay

Replay-ay-ay-ay

Shawty's like a melody in my head

That I can't keep out

Got me singin' like Na na na na everyday

It's like my iPod's stuck on replay

Replay-ay-ay-ay the pesrson above me is right got 100 on k12

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If you pull a permanent magnet rapidly away from a tank circuit, what is likely to happen in that circuit?

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3 years ago

A 45.0-N force pushes a cart 12.5 meters down a hallway. What is the work done on the cart?

makvit [3.9K]

Answer:

562.5J

Explanation:

The following were obtained from the question:

F = 45N

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3 0

3 years ago

Chapter 21, Problem 009 Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of 0.12

PilotLPTM [1.2K]

Answer:

a) -1.325 μC

b) 4.17μC

Explanation:

First, you need to know that charge is conserved. So, the adition of the charges, as there is no lost in charge, should always be the same. Also, after the wire is removed, both spheres will have the same charge, trying to find equilibrium. In summary:

$q_1 + q_2 = constant\\q_1_f = q_2_f |Then\\q_1_f + q_2_f = 2q_1_f = q_1_o+q_2_o\\q_1_f = q_2_f = \frac{q_1_o+q_2_o}{2}$

We know both q1f and q2f must be positive, because the negative charge at the beginning was the the smaller.

The electrostatic force is equal to:

$F_e = k\frac{q_1q_2}{r^2}$

K is the Coulomb constant, equal to 9*10^9 Nm^2/C^2

Now, we are told that the electrostatic force after the wire is equal to 0.0443 N:

$F_e_f = k \frac{q_1_fq_2_f}{r^2} = k\frac{\frac{q_1_o+q_2_o}{2}\frac{q_1_o+q_2_o}{2}}{r^2} = k\frac{(q_1_o+q_2_o)^2}{4r^2} \\(q_1_o+q_2_o) = \sqrt{\frac{F_e_f*4r^2}{k}} = \sqrt{\frac{0.0443N *4(0.641m)^2}{9*10^9Nm^2/C^2} } = 2.844 *10^{-6}C \\ q_1_o = 2.844*10^{-6}C - q_2_o$

Originally, the force is negative because it was an attraction force, therefore, its direction was opposite to the direction of the repulsive force after the wire:

$F_e_o = k\frac{q_1_oq_2_o}{r^2}\\ q_1_oq_2_o = \frac{F_e_o*r^2}{k} = \frac{-0.121N(0.641m)^2}{9*10^9Nm^2/C^2} = -5.524*10^{-12}$

$(2.844*10^{-6}C - q_2_o)q_2_o = -5.524*10^{-12}\\0 = q_2_o^2 - 2.844*10^{-6}q_2_o - 5.524*10^{-12}$

Solving the quadratic equation:

$q_2_o = 4.17*10^{-6}C | -1.325 * 10^{-6}C$

for this values q_1 wil be:

$q_1_o = -1.325 *10^{-6}C | 4.17*10^{-6}C$

So as you can see, the negative charge will always be -1.325 μC and the positive 4.17μC

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3 years ago

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