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aleksley [76]
3 years ago
14

The electric field in a region is uniform (constant in space) and given by E-( 148.0 1 -110.03)N/C. An additional charge 10.4 nC

(nano-coulombs) is placed into this region. What is the y component of the electric force on this charge?
Physics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

-1.144\ \mu C

Explanation:

<u>Given:</u>

  • \vec{E} = uniform electric field in the space = (148.0\ \hat{i}-110.0\ \hat{j})\ N/C
  • Q = Charge placed in the region = 10.4 nC\ = 1.04\times 10^{-8}\ nC

<u>Assume:</u>

  • \vec{F} = Electric force on the charge due to electric field

We know that the electric field is the electric force applied on a unit positive charge i.e.,

\vec{E}=\dfrac{\vec{F}}{Q}

This means the electric force applied on this additional charge placed in the field is given by:

\vec{F}=Q\vec{E}\\\Rightarrow \vec{F} =  1.04\times 10^{-8}\ n C\times (148.0\ \hat{i}-110.0\ \hat{j})\ N/C\\\Rightarrow \vec{F} = (1.539\ \hat{i}-1.144\ \hat{j})\ \mu N\\

From the above expression of force, we have the following y-component of force on this additional charge.

F_y = -1.144\ \mu N

Hence, the y-component of the electric force on the this charge is -1.144\ \mu N.

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