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Nataly [62]
3 years ago
5

Given the two sets, which statement is true? A = {1, 2} B = {1, 2, 3, 4}

Physics
1 answer:
Mnenie [13.5K]3 years ago
3 0
What are the two sets? I only see the two answers?
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What if energy, like electricity, could not be converted to other forms like sound, heat, motion, or light?
EleoNora [17]

Answer: It wouldn't be as modern as today is we would be back to using oil and other things from back then there wouldn't be cars everything would be less machined.

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3 years ago
A 7.00 kg bowling ball is held 2.00 m above the ground. Using g- 9.8 m/s^2, how much energy does the bowling ball have due to it
Alexeev081 [22]
It should be B.137 just took the test.
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3 years ago
1. A car starting from rest accelerates uniformly at 3
amid [387]

The car's final speed in  m/s after the acceleration is 30.

<u />

<u>Given the following data:</u>

  • Initial velocity, U = 0 m/s (since the cars starts from rest)
  • Time, t = 10 seconds
  • Acceleration, a = 3 meter per seconds square.

To find the car's final speed in  m/s after the acceleration, we would use the first equation of motion;

Mathematically, the first equation of motion is given by the formula;

V = U + at\\\\V = 0 + 3(10)

<em>Final speed, V </em><em>=</em><em> 30 m/s</em>

Therefore, the car's final speed in  m/s after the acceleration is 30.

Read more: brainly.com/question/8898885

5 0
3 years ago
How much time will it take to do 33j of work with 11 w of power
Yuri [45]

Time required : 3 s

<h3>Further explanation </h3>

Power is the work done/second.

\tt P=\dfrac{W}{t}\\\\P=power,j/s,watt\\\\W=work, J\\\\t=times=s

 

To do 33 J of work with 11 W of power

P = 11 W

W = 33 J

\tt t=\dfrac{W}{P}\\\\t=\dfrac{33}{11}\\\\t=\boxed{\bold{3~s}}

8 0
3 years ago
The average specific heat of the human body is 3.6 kJ/kg·°C. If the body temperature of a(n) 96-kg man rises from 37°C to 39°C d
d1i1m1o1n [39]

Answer:

691200 J

Explanation:

From specific heat capacity,

ΔQ = cmΔt.................. Equation 1

Where ΔQ = increase in thermal energy, c = specific heat capacity of the body, m = mass of the man, Δt = rise in temperature.

Given: c = 3.6 kJ/kg.°C = 3600 J/kg.°C, m = 96 kg, Δt = 39-37 = 2 °C.

Substitute into equation 1

ΔQ = 3600×96×2

ΔQ = 691200 J.

Hence the change in the thermal energy of the body = 691200 J

5 0
3 years ago
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