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Nataly [62]
3 years ago
5

Given the two sets, which statement is true? A = {1, 2} B = {1, 2, 3, 4}

Physics
1 answer:
Mnenie [13.5K]3 years ago
3 0
What are the two sets? I only see the two answers?
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Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 403 km above the earth’s sur
BARSIC [14]

Answer:

v_A=7667m/s\\\\v_B=7487m/s

Explanation:

The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:

F_g=\frac{GMm}{R^{2} }

Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.

Also, we know that the centripetal force of an object describing a circular motion is given by:

F_c=m\frac{v^{2}}{R}

Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.

Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:

\frac{GMm}{R^2}=m\frac{v^2}{R}\\ \\\implies v=\sqrt{\frac{GM}{R}}

Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So R_A=6774km=6.774*10^6m and R_B=7103km=7.103*10^6m (Since R_{earth}=6371km). Then, we get:

v_A=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{6.774*10^6m} }=7667m/s\\\\v_B=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{7.103*10^6m} }=7487m/s

In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).

7 0
2 years ago
Highlight two factors which shows that heat from the sun does reach the earth's surface by convection.
MAXImum [283]

radiation

when the suns radiation fall on the earth and its objects they receive heat energy and hence get heated. Thus the suns heat reaches the earth by. the process of radiation

3 0
2 years ago
Greyhound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but
maw [93]

{\large{\bold{\rm{\underline{Given \; that}}}}}

★ A grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.

{\large{\bold{\rm{\underline{To\; find}}}}}

★ The speed of the hound and the hare

{\large{\bold{\rm{\underline{Solution}}}}}

★ The speed of the hound and the hare = 25:18

{\large{\bold{\rm{\underline{Full \; Solution}}}}}

\dashrightarrow  As it's given that a grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.

 So firstly let us assume a metres as the distance covered by the hare in one leap.

Ok now let's talk about 5 leaps,.! As it's cleared that the hare cover the distance of 5a metres.

 But 3 leaps of the hound are equal to 5 leaps of the hare.

Henceforth, (5/3)a meters is the distance that is covered by the hound.

 Now according to the question,

Hound pursues a hare and takes 5 leaps for every 6 leaps of the hare..! (Same interval)

Now the distance travelled by the hound in it's 5 leaps..!

  • (5/3)a × 5

  • 25/3a metres

 Now the distance travelled by the hare in it's 6 leaps..!

  • 6a metres

 Now let us compare the speed of the hound and the hare. Let us calculate them in the form of ratio..!

  • 25/3a = 6a

  • 25/3 = 6

  • 25:18
5 0
3 years ago
Which of the following in the list is the best conductor: plastic, metal, styrofoam, or glass?
tensa zangetsu [6.8K]

Answer:

Metal

Explanation:

3 0
2 years ago
Read 2 more answers
What is the kinetic energy of a 1200 kg object that is moving at a speed of 24 m/s?
maria [59]
Kinetic Energy = 1/2mv^2
m= 1200kg
v= 24 m/s

KE = 1/2 (1200kg)(24m/s)^2 = 345,600 N
4 0
3 years ago
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