During a medieval siege of a castle, the attacking army uses a trebuchet to heavy stones at the castle the trebuchet launches th
e stones with a velocity of + 48.5 m/s at an angle of 42.0 degrees how long does take the stone to hit the ground? For those settings, what is the maximum How high will the stones go Show all your work
1 answer:
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Answer:
299.88 kgm²/s
499.758 kgm²/s
Explanation:
R = Radius of merry-go-round = 1.63 m
I = Moment of inertia = 196 kgm²
= Initial angular velocity = 1.53 rad/s
m = Mass of person = 73 kg
v = Velocity = 4.2 m/s
Initial angular momentum is given by
The initial angular momentum of the merry-go-round is 299.88 kgm²/s
Angular momentum is given by
The angular momentum of the person 2 meters before she jumps on the merry-go-round is 499.758 kgm²/s