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Kisachek [45]
2 years ago
14

During a medieval siege of a castle, the attacking army uses a trebuchet to heavy stones at the castle the trebuchet launches th

e stones with a velocity of + 48.5 m/s at an angle of 42.0 degrees how long does take the stone to hit the ground? For those settings, what is the maximum How high will the stones go Show all your work

Physics
1 answer:
vlada-n [284]2 years ago
7 0

Answer:

Explanation:

The question relates to time of flight of a projectile .

Time of flight = 2 u sinθ / g

u is speed of projectile , θ is angle of projectile

= 2 x 48.5 sin42 / 9.8

= 6.6 seconds  .

Maximum height attained

= u² sin²θ / g

= 48.5² sin²42 / 9.8

= 107.47 m .

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