During a medieval siege of a castle, the attacking army uses a trebuchet to heavy stones at the castle the trebuchet launches th
e stones with a velocity of + 48.5 m/s at an angle of 42.0 degrees how long does take the stone to hit the ground? For those settings, what is the maximum How high will the stones go Show all your work
1 answer:
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Answer:
The change in potential energy and kinetic energy are 980 MJ and 148.3 MJ.
Explanation:
Given that,
Mass of aircraft = 10000 kg
Speed = 620 km/h = 172.22 m/s
Altitude = 10 km = 1000 m
We calculate the change in potential energy
For g = 10 m/s²,
The change in potential energy will be 1000 MJ.
We calculate the change in kinetic energy
For g = 10 m/s²,
The change in kinetic energy will be 150 MJ.
Hence, The change in potential energy and kinetic energy are 980 MJ and 148.3 MJ.
≈40.8kg
this is to take up space
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
