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3 years ago

A 1,500-kg truck has a net force of 4,200 N acting on it. What is the truck’s acceleration?

Physics

1 answer:

sweet [91]3 years ago

6 0

Answer:

Acceleration = 2.8 m/s²

Explanation:

Given the following data;

Mass = 1500 kg

Net force = 4200 Newton

To find the truck's acceleration;

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

$Acceleration = \frac {Net \; force}{mass}$

Substituting into the formula, we have;

$Acceleration = \frac {4200}{1500}$

Acceleration = 2.8 m/s²

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The electron density in copper is 8.49 × 1028 electrons/m3. When a 1.00 A current is present in a copper wire with a 0.40 cm2 cr

vichka [17]

Answer:

Drift velocity in m/s is $1.84 \times 10^{-8}\ m/s$ .

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<em>Formula for Drift Velocity is</em>:

$u = \dfrac{I}{nAq}$

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q is the charge of one electron.

We are given the following:

n = $8.49 \times 10^{28}\ electrons/m^3$

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We know that q = $1.6\times10^{-19} C$

Putting all the values to find drift velocity:

$u = \dfrac{1}{8.49 \times 10 ^{28} \times 40 \times 10^{-4}\times 1.6 \times 10^{-19}}\\u = \dfrac{1}{543.36 \times 10 ^{5} }\\u = 1.84 \times 10^{-8}\ m/s$

So, <em>drift velocity in m/s</em> is $1.84 \times 10^{-8}\ m/s$ .

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