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hjlf
3 years ago
7

The electron density in copper is 8.49 × 1028 electrons/m3. When a 1.00 A current is present in a copper wire with a 0.40 cm2 cr

oss-section, the electron drift velocity, in m/s, with direction defined relative to the current density, is
Physics
1 answer:
vichka [17]3 years ago
3 0

Answer:

Drift velocity in m/s is 1.84 \times 10^{-8}\ m/s.

Explanation:

<em>Formula for Drift Velocity is</em>:

u = \dfrac{I}{nAq}

Where I is the current

n is the number of electrons in 1 m^3 or the electron density

A is the area of cross section and

q is the charge of one electron.

We are given the following:

n = 8.49 \times 10^{28}\ electrons/m^3

I = 1 A

A = 0.40 cm^2 = 40 \times 10^{-4} m^{2}

We know that q = 1.6\times10^{-19} C

Putting all the values to find drift velocity:

u = \dfrac{1}{8.49 \times 10 ^{28} \times 40 \times 10^{-4}\times 1.6 \times 10^{-19}}\\u = \dfrac{1}{543.36 \times 10 ^{5} }\\u = 1.84 \times 10^{-8}\ m/s

So, <em>drift velocity in m/s</em> is 1.84 \times 10^{-8}\ m/s.

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