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MissTica
3 years ago
13

Please need help on these

Physics
1 answer:
Alborosie3 years ago
7 0

question 6 is global warming and question 7 is carbon dioxide

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A 230 kg steel crate is being pushed along a cement floor. The force of friction is 480 N to the left and the applied force is 1
tamaranim1 [39]
The acceleration would be 6m/sThis is because of the formula, "f/m=a" to find the acceleration; We would need to subtract the force of the friction which equals 1380, then divide that by the mass (which was 230) to get the answer 6
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4 years ago
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How does Newton's second law of motion can be used to calculate the acceleration of an object?
Alex777 [14]

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

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A basketball player spins the ball with an angular acceleration of 10 rad/s2. What is the ball’s final angular velocity if the b
Lena [83]

Explanation:

It is given that,

The angular acceleration of the basketball, \alpha=10\ rad/s^2

Time taken, t = 3 seconds

We need to find the ball’s final angular velocity if the ball starts from rest. It can be calculated using definition of angular acceleration i.e.

\alpha=\dfrac{\omega_f-\omega_i}{t}

\omega_i=0\ (rest)

\omega_f=\alpha t

\omega_f=10\ rad/s^2\times 3\ s

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3 years ago
A brass cube, 10 cm on a side, is raised in temperature
lana [24]

Answer:

\delta L\%=22.5\%

Explanation:

<em>Assuming that the thermal expansion of brass cube occurs isotropically (i.e. equal in all the directions).</em>

Given:

  • length of the cube, l=10\ cm=0.1\ m
  • change in temperature of the cube, \Deta T=200\^{\circ}C
  • coefficient of volume expansion, \beta=57\times 10^{-6}\ ^{\circ}C^{-1}

<u>Hence volume of the cube:</u>

V=10^{-3}\ m^3

Now the volume of the cube after expansion:

\delta V=V.\beta.\Delta T

\delta V=10^{-3}\times 57\times 10^{-6}\times 200

\delta V=1.14\times 10^{-5}\ m^3

Therefore,

\delta L=0.0225\ m

<u>Now the percentage change in the edges of the cube:</u>

\delta L\%=\frac{\delta L}{L} \times 100

\delta L\%=\frac{0.0225}{0.1} \times 100

\delta L\%=22.5\%

5 0
3 years ago
On his way to school, a student starts out walking quickly and then slows down as he gets closer to the school. Which graph best
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' A ' is the graph that shows it.

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4 years ago
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