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tatyana61 [14]
3 years ago
13

Astronaut Neil during his lunar mission recorded his weight. He noticed a big difference in his weight compared to his weight ta

ken when he was on earth. If his weight on earth was 90kgs, what would be his weight on moon and what could be the reason for this difference?
a. His weight will be 5kg; this is because moon’s gravity is 1/10th as compared to that of the earth.
b. His weight will be 45kg; this is because moon’s gravity is 1/7th as compared to that of the earth.
c. His weight will be 5kg; this is because moon’s gravity is 1/8th as compared to that of the earth.
d. His weight will be 15kg; this is because moon’s gravity is 1/6th as compared to that of the earth.
Physics
1 answer:
Aleks [24]3 years ago
6 0

Answer:

no entiendo

Explanation:

esta en ingles

You might be interested in
A frictionless piston–cylinder device contains 7 kg of nitrogen at 100 kPa and 250 K. Nitrogen is now compressed slowly accordin
lora16 [44]

Answer: -1038.8 kJ

Explanation:

From the question, we can see that PV^n = constant. And as such, we can deduce that it is a polytropic process. Thus, we can use the polytropic work equation to calculate the needed work input.

from the question we were given

Mass of nitrogen, m = 7kg

initial temperature, T1 = 250k

Final temperature, T2 = 450k

Polytropic index, n = 1.4

Specific gas constant, R = 0.2968kJ/kgK

W = [p2 * v2 - p1 * v1] / 1 - n

W = [m * R * T2 - T1] / 1 - n

W = 7*0.2968*(450 - 250)] / 1 - 1.4

W = [7*0.2968*200] / -0.4

W = 415.52 / -0.4

W = -1038.8 kJ

5 0
3 years ago
Ice has a density of 0.920 g/cm3. An ice cubes mass is 100 g. What is its volume?
Tasya [4]

Answer:

\boxed {\tt 108.695652 \ cm^3}

Explanation:

Volume can be found by dividing the mass by the density.

v=\frac{m}{d}

The mass is 100 grams and density is 0.920 grams per cubic centimeters.

Therefore,

m=100 \ g \\d= 0.920 \ g/cm^3

Substitute the values into the formula.

v=\frac{100 \ g}{0.920 \ g/cm^3}

Divide. Note that the grams, or "g" will cancel each other out.

v- 108.695652 \ cm^3

The volume of the ice cube is 108.697652 cubic centimeters.

3 0
3 years ago
Create the following matrix H:
sladkih [1.3K]

Answer:

a) {[1.25  1.5  1.75  2.5  2.75]

    [35  30  25  20  15]  }

b) {[1.5  2  40]

    [1.75  3  35]

    [2.25  2  25]

    [2.75  4  15]}

Explanation:

Matrix H: {[1.25  1.5  1.75  2  2.25  2.5  2.75]

                [1  2  3  1  2  3  4]

                [45  40  35  30  25  20  15]}

Its always important to get the dimensions of your matrix right. "Roman Columns" is the mental heuristic I use since a matrix is defined by its rows first and then its column such that a 2 X 5 matrix has 2 rows and 5 columns.

Next, it helps in the beginning to think of a matrix as a grid, labeling your rows  with letters (A, B, C, ...) and your columns with numbers (1, 2, 3, ...).

For question a, we just want to take the elements A1, A2, A3, A6 and A7 from matrix H and make that the first row of matrix G. And then we will take the elements B3, B4, B5, B6 and B7 from matrix H as our second row in matrix G.

For question b, we will be taking columns from matrix H and making them rows in our matrix K. The second column of H looks like this:

{[1.5]

[2]

[40]}

Transposing this column will make our first row of K look like this:

{[1.5  2  40]}

Repeating for columns 3, 5 and 7 will give us the final matrix K as seen above.

4 0
3 years ago
The wave produced by a piano's middle C has a frequency of 440 Hz
bogdanovich [222]

Answer:

0.78 m

Explanation:

I just did a hw question for this its just 344  divided by 440

3 0
3 years ago
A 7.59-m-tall container is filled to the brim, partway with mercury and the rest of the way with water. The container is open to
hoa [83]

Answer:

0.22 m

Explanation:

P_{o} = Atmospheric pressure = 101325 Pa

P = Pressure at the bottom = tex]2 P_{o}[/tex] = 2 (101325) = 202650 Pa

h = height of the container = 7.59 m

x = depth of the mercury

Pressure at the bottom = Atmospheric pressure + Pressure due to mercury + Pressure due to water

P = P_{o} + \rho _{w} g (h - x) + \rho _{hg} g x\\2 P_{o} = P_{o} + \rho _{w} g (h - x) + \rho _{hg} g x\\P_{o} = \rho _{w} g (h - x) + \rho _{hg} g x\\101325 = (1000) (9.8) (7.59 - x) + (13600) (9.8) x\\x = 0.22 m

5 0
4 years ago
Read 2 more answers
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