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NikAS [45]
3 years ago
5

Ch3ch(cl)ch2ch3+koh=?

Chemistry
1 answer:
netineya [11]3 years ago
4 0

words of wisdom.......

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What is the purpose of strawberry seeds
Butoxors [25]

Answer:

To help spread seeds to make more strawberries. Once a person bites into a strawberry some of the seeds fall and help plant new ones.

Explanation:

Hope this helps:)

7 0
4 years ago
Murcury is the only metal at room temperature. Its density is 13.6g/mL. How many grams of murcury will occupy a volume of 95.8mL
Hatshy [7]

Answer:

<h3>The answer is 1.30288 × 10³ g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 95.8mL

density = 13.6g/mL

We have

mass = 13.6 × 95.8 = 1302.88

We have the final answer as

<h3>1.30288 × 10³ g</h3>

Hope this helps you

3 0
3 years ago
Rasheed calculates that his chemical reaction should produce 4 moles of product, but when he does the experiment, he gets only 3
Brut [27]

Answer:

The answer to your question is 75%

Explanation:

Data

Theoretical production = 4 moles

Experimental production = 3 moles

Percent yield = ?

Formula

Percent yield = \frac{Experimental production}{Theoretical production} x 100

Substitution

Percent yield = \frac{3}{4} x 100

Result

Percent yield = 75 %

8 0
4 years ago
A certain substance melts at a temperature of . But if a sample of is prepared with of urea dissolved in it, the sample is found
pshichka [43]

Answer:

2.2 °C/m

Explanation:

It seems the question is incomplete. However, this problem has been found in a web search, with values as follow:

" A certain substance X melts at a temperature of -9.9 °C. But if a 350 g sample of X is prepared with 31.8 g of urea (CH₄N₂O) dissolved in it, the sample is found to have a melting point of -13.2°C instead. Calculate the molal freezing point depression constant of X. Round your answer to 2 significant digits. "

So we use the formula for <em>freezing point depression</em>:

  • ΔTf = Kf * m

In this case, ΔTf = 13.2 - 9.9 = 3.3°C

m is the molality (moles solute/kg solvent)

  • 350 g X ⇒ 350/1000 = 0.35 kg X
  • 31.8 g Urea ÷ 60 g/mol = 0.53 mol Urea

Molality = 0.53 / 0.35 = 1.51 m

So now we have all the required data to <u>solve for Kf</u>:

  • ΔTf = Kf * m
  • 3.3 °C = Kf * 1.51 m
  • Kf = 2.2 °C/m
5 0
3 years ago
A balloon that contains 0.750 moles of gas has a volume of 16.8 L. If additional gas causes the balloon to expand to a volume of
mixas84 [53]

the answer is 1.13 moles

5 0
3 years ago
Read 2 more answers
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