Answer:
32.3 dm³
Explanation:
Data given:
no. of molecules of Cl₂ = 8.7 x 10²³
Volume of chlorine gas (Cl₂) = ?
Solution:
First we have to find number of moles
For this formula used
no. of moles = no. of molecules / Avogadros number
no. of moles = 8.7 x 10²³ / 6.022 x 10²³
no. of moles = 1.44 moles
Now we have to find volume of the gas
for this formula used
no. of moles = volume of gas / molar volume
molar volume = 22.4 dm³/mol
Put values in above equation
1.44 moles = volume of Cl₂ gas / 22.4 dm³/mol
rearrange the above equation
volume of Cl₂ gas = 1.44 moles x 22.4 dm³/mol
volume of Cl₂ gas = 32.3 dm³
Answer:
Wavelength (λ) – The distance of one complete cycle in the wave. The distance between two consecutive crests and /or troughs. S.I. Unit: metre (m).
In other words:
Wavelength is the distance from crest to crest (or trough to trough).
In Ni(CO)₄ the stoichiometry of Ni to C is 1:4
for every 4 atoms of C is attached to one Ni atom.
this means that if there are 4 atoms of C - 1 atom of Ni
in 5.23 x 10²⁴ atoms of C -1/4 x 5.23 x 10²⁴ atoms of Ni
= 1.3075 x 10²⁴ atoms of Ni
the number of atoms rounded off to the second decimal place = 1.31 x 10²⁴ atoms
correct answer is E
Answer:
Q1. 0.82 mol
Q2. 9.20 g
Explanation:
Question 1
Step 1: Given and required data
- Mass of NaHCO₃ (m): 68.88 g
- Molar mass of NaHCO₃ (M): 84.01 g/mol
Step 2: Calculate the moles (n) corresponding to 68.88 g of NaHCO₃
We will use the following expression.
n = m/M
n = 68.88 g/(84.01 g/mol) = 0.82 mol
Question 2
Step 1: Given data
- Moles of NaOH (n): 0.23 mol
- Molar mass of NaOH (M): 40.00 g/mol
Step 2: Calculate the mass (m) corresponding to 0.23 moles of NaOH
We will use the following expression.
m = n × M
m = 0.23 mol × 40.00 g/mol = 9.20 g
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