Answer:
A. He sent a cathode ray between electrically charged metal plates
<span>Molten barium
chloride is separetes:</span><span>
BaCl</span>₂(l) →
Ba(l) + Cl₂(g), <span>
but first ionic bonds in this salt are separeted
because of heat:
BaCl</span>₂(l) →
Ba²⁺(l) + 2Cl⁻(l).
Reaction of reduction
at cathode(-): Ba²⁺(l) + 2e⁻ → Ba(l).
Reaction of oxidation
at anode(+): 2Cl⁻(l) → Cl₂(g) + 2e⁻.
The anode is positive
and the cathode is negative.
<u>Answer:</u> The empirical formula for the given compound is 
<u>Explanation:</u>
We are given:
Mass of pure compound containing copper and sulfur = 4.963 g
Mass of S = 1.000 g
Mass of Cu = (4.963 - 1.000) g = 3.963 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Copper =
Moles of Sulfur = 
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0312 moles.
For Copper = 
For Sulfur = 
<u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of Cu : S = 2 : 1
Hence, the empirical formula for the given compound is 
The answers that are correct are a, b, and d
Answer:
There are 3 non-metals in benzoic acid.
Explanation:
They are Hydrogen, Oxygen, and Carbon.