If BD is both the altitude and median of ΔABC then ΔABC is ____

Dimas [21]

It is number 3. Have a good day.

3 0

2 years ago

A pet store has three aquariums for fish. Aquarium A contains 24 fish, Aquarium B contains 51 fish, and Aquarium C contains 36 f

bazaltina [42]

The graph that can represent the data most accurately is (a) The y-axis of a bar graph starts at zero fish. One bar is 24 units, another bar is 51 units, and the third bar is 36 units

The given parameters are:

Aquarium A: 24 fishes
Aquarium B: 51 fishes
Aquarium C: 36 fishes

The above dataset can be represented on a bar graph, where the lengths of the bars represent the number of fishes in each aquarium

Hence, the graph that can represent the data most accurately is (a)

Read more about graphs at:

brainly.com/question/25677468

5 0

2 years ago

Which statement best explains the importance of examining multiple perspectives about an event?

belka [17]

Answer:

It provides different and sometimes opposing viewpoints about an event.

3 0

2 years ago

Consider points A (3, 6) and B (8, 4). Find point C on the x-axis so AC + BC is a

scoray [572]

Answer:

(1,2)

Step-by-step explanation:

the st. lines 3x+4y=5 and 4x-3y=15 interrect at a point A(3, -1. On these linepoints B and C are chosen so that AB= AC. find the posible eqns of the lineBC pathrough the point

6 0

2 years ago

Evaluate the following integral using trigonometric substitution

serg [7]

Answer:

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

Step-by-step explanation:

We are given the following integral:

$\int \frac{dx}{\sqrt{9-x^2}}$

Trigonometric substitution:

We have the term in the following format: $a^2 - x^2$ , in which a = 3.

In this case, the substitution is given by:

$x = a\sin{\theta}$

So

$dx = a\cos{\theta}d\theta$

In this question:

$a = 3$

$x = 3\sin{\theta}$

$dx = 3\cos{\theta}d\theta$

So

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}$

We have the following trigonometric identity:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

So

$1 - \sin^{2}{\theta} = \cos^{2}{\theta}$

Replacing into the integral:

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C$