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2 years ago

A person invested $7,400 in an account growing at a rate allowing the money to

Mathematics

1 answer:

Reil [10]2 years ago

8 0

Answer:

well the money doubles every 6 years but its only been 4 so

7,400 x 4 = 29,600

$29,600 is the answer

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Slope of -8,4 and 3,-4

nata0808 [166]

For this case we have that by definition, the slope of a line is given by:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}$

Where:

$(x_ {1}, y_ {1})$ and $(x_ {2}, y_ {2})$ are two points through which the line passes

According to the statement we have:

$(x_ {1}, y_ {1}): (- 8,4)\\(x_ {2}, y_ {2}) :( 3, -4)$

Substituting we have:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-4-4} {3 - (- 8)} = \frac {-8} {3 + 8} = \frac {-8} {11} = - \frac {8} {11}$

Thus, the slope of the line is:

$m = - \frac {8} {11}$

Answer:

$m = - \frac {8} {11}$

3 0

3 years ago

Help I don’t understand this

bogdanovich [222]

Answer:

tan 33° = 25/x

Step-by-step explanation:

hope it helps

5 0

3 years ago

Too stoned help pls

podryga [215]

Distributive proeprty
wait
combein elike terms
4(1m+3+5m)=4(5m+1m+3)=4(6m+3)

if we distribute
reemmber that a(b+c)=ab+ac
4(6m+3)=4(6m)+4(3)=24m+12

A. 24m+12 and 12(2m+1)
B. distributive property
C. if m=1, we get 36=36

3 0

3 years ago

Find the area of the shaded part of the triangle below. Round to the nearest tenth if needed.

konstantin123 [22]

Answer:

212.5

Step-by-step explanation:

For triangles, A = (bh)/2

You can do 15+25 to find the base, which is 40. From here do 17*40/2. You get 340. However, you need to remove the right triangle on the left side.

Again do 17*15/2, which you get 127.5.

From here subtract 127.5 from 340 and get 212.5

7 0

3 years ago

Read 2 more answers

Suppose that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective. Consider randomly selecting thre

Andrew [12]

Answer:

Step-by-step explanation:

Given that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective.

Probability for any one to be defective as of now is $\frac{36}{45} =0.80$

a) $P(E) = 0.80$

b) After I draw we have 35 good ones and 9 defective

P(F/E) = $\frac{35}{44} \\=0.796$

c) P(G/EF)

This is the probability for iii bulb to be good given I and II are goog.

Once I and ii are good we have 43 bulbs with 34 good ones

$P(G/EF) =\frac{34}{43} \\=0.7907$

5 0

2 years ago