You should see the denominator of the function in this case. 6x ^ 2-7x-3 We see where the denominator becomes zero: 6x ^ 2-7x-3 = 0 x1 = 3/2 x2 = -1 / 3 The function is discontinuous in those two points. Therefore, it has vertical asymptotes in: x1 = 3/2 x2 = -1 / 3 answer: has vertical asymptotes in: x1 = 3/2 x2 = -1 / 3 option 1
