200-144=56
56/2=28
Neil is 28
You would pay $33 for the bracelet
Answer:
(x, y) = (1, 3)
Step-by-step explanation:
given the 2 equations
x + y = 4 → (1)
y = 3x → (2)
Substitute y = 3x into (1)
x + 3x = 4
4x = 4 ( divide both sides by 4 )
x = 1
Substitute x = 1 into (2) for corresponding value of y
y = 3 × 1 = 3
solution is (1, 3 )
<h3>
Answer:</h3>
- <u>20</u> kg of 20%
- <u>80</u> kg of 60%
<h3>
Step-by-step explanation:</h3>
I like to use a little X diagram to work mixture problems like this. The constituent concentrations are on the left; the desired mix is in the middle, and the right legs of the X show the differences along the diagonal. These are the ratio numbers for the constituents. Reducing the ratio 32:8 gives 4:1, which totals 5 "ratio units". We need a total of 100 kg of alloy, so each "ratio unit" stands for 100 kg/5 = 20 kg of constituent.
That is, we need 80 kg of 60% alloy and 20 kg of 20% alloy for the product.
_____
<em>Using an equation</em>
If you want to write an equation for the amount of contributing alloy, it works best to let a variable represent the quantity of the highest-concentration contributor, the 60% alloy. Using x for the quantity of that (in kg), the amount of copper in the final alloy is ...
... 0.60x + 0.20(100 -x) = 0.52·100
... 0.40x = 32 . . . . . . . . . . .collect terms, subtract 20
... x = 32/0.40 = 80 . . . . . kg of 60% alloy
... (100 -80) = 20 . . . . . . . .kg of 20% alloy
M can have any value because M can represent any number because it is the unknown.