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sdas [7]
2 years ago
9

Multiple choice question

Mathematics
1 answer:
konstantin123 [22]2 years ago
7 0

Answer:

b. g(x)=|x+3|-1

Step-by-step explanation:

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How old is Neil if 200 reduced by 2 times his<br> age is 144?
Dmitry [639]
200-144=56
56/2=28
Neil is 28
8 0
3 years ago
A bracelet that regularly sells for $44 is on sale for 25% off. Find the sale price of the bracelet.
VikaD [51]
You would pay $33 for the bracelet 
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2 years ago
Solve the system of equations by substitution
scoundrel [369]

Answer:

(x, y) = (1, 3)

Step-by-step explanation:

given the 2 equations

x + y = 4 → (1)

y = 3x → (2)

Substitute y = 3x into (1)

x + 3x = 4

4x = 4 ( divide both sides by 4 )

x = 1

Substitute x = 1 into (2) for corresponding value of y

y = 3 × 1 = 3

solution is (1, 3 )


7 0
3 years ago
A metalworker has a metal alloy that is 20​% copper and another alloy that is 60​% copper. How many kilograms of each alloy shou
puteri [66]
<h3>Answer:</h3>
  • <u>20</u> kg of 20%
  • <u>80</u> kg of 60%
<h3>Step-by-step explanation:</h3>

I like to use a little X diagram to work mixture problems like this. The constituent concentrations are on the left; the desired mix is in the middle, and the right legs of the X show the differences along the diagonal. These are the ratio numbers for the constituents. Reducing the ratio 32:8 gives 4:1, which totals 5 "ratio units". We need a total of 100 kg of alloy, so each "ratio unit" stands for 100 kg/5 = 20 kg of constituent.

That is, we need 80 kg of 60% alloy and 20 kg of 20% alloy for the product.

_____

<em>Using an equation</em>

If you want to write an equation for the amount of contributing alloy, it works best to let a variable represent the quantity of the highest-concentration contributor, the 60% alloy. Using x for the quantity of that (in kg), the amount of copper in the final alloy is ...

... 0.60x + 0.20(100 -x) = 0.52·100

... 0.40x = 32 . . . . . . . . . . .collect terms, subtract 20

... x = 32/0.40 = 80 . . . . . kg of 60% alloy

... (100 -80) = 20 . . . . . . . .kg of 20% alloy

6 0
3 years ago
In m + 8, the variable m can have any value. Tell whether each statement is true or false. Then explsin your reasoning.
mote1985 [20]
M can have any value because M can represent any number because it is the unknown.
4 0
3 years ago
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