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UNO [17]
3 years ago
6

Write the slope intercept form of the equation of each line given the slope and y-intercept.

Mathematics
1 answer:
Gre4nikov [31]3 years ago
8 0

Answer:

Answer would be :

1) Y= -1X-5

2)Y= -1X-1

3)Y= 3/2X

4) Y= -3/4X -4

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Multiplication always sometimes or never true
mixas84 [53]
Always true,hope I have helped
5 0
3 years ago
Solve using elimination 5x+7y=9 <br> 2x-3y=-37
uranmaximum [27]

Answer:

x = -8

y = 7

Step-by-step explanation:

5x + 7y = 9

2x - 3y = -37

1.) First, multiply each side to match either y-values or x-values. (In this example, we'll use match x-values)

10x + 14y = 18 (multiplied by 2)

10x - 15y = -185 (multiplied by 5)

2.) Then, subtract the entirety of one equation to isolate the y-value.

10x + 14y = 18

-10x + 15y = 185

3.) Add and subtract values and divide to find y.

29y = 203

y = 7

4.) Plug-in y to solve for x into one equation, or repeat steps 1-3.

15x + 21y = 27

14x - 21y = -259

29x = -232

x = -8

4 0
2 years ago
WILL GIVE BRAINLIEST&amp; 15 PTS.
kicyunya [14]

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

6 0
3 years ago
Read 2 more answers
Will give brainliest :)
Whitepunk [10]

Answer:

90 degrees

Step-by-step explanation:

BCO = 66

The whole ABC is 180

So BCO and  BDO = 90

Therefore BAO must = 90 degrees

5 0
3 years ago
How many years will it take for the account to reach $18,600? Round your answer to the nearest hundredth
Margarita [4]
 <span>it depends how the interest is calculated, but there's not much of a difference 

assuming its continuously compouned, you use this formula: A(t)=Pe^(rt), where A is the final amount, P is the initial investment, r is the interest, and t is the time in years 

you want to find t such that A(t)=18,600 so 18,600=1000e^(.0675t) 

you need to use logarithm to figure it out, take the natural log of both sides 

the following properties will come into use: 

ln(a*b)=ln(a)+ln(b) 
ln(a^b)=bln(a) 
ln(e)=1 

taking the natural log 

ln(18,600)=ln(1000e^(.0675t)) 

ln(18,600)=ln(1000)+ln(e^.0675t) 

ln(18600)=ln(1000) + .0675t 

now solve for t: t= (ln(18600)-ln(1000))/.0675 

t=43.31</span>
4 0
3 years ago
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