The complete question in the attached figure
we know that
m∡4=65°
m∡4=m∡2---------> by internal alternate angles
m∡5=m∡3---------> by internal alternate angles
m∡1=180°-m∡2---------> 180°-65°--------> m∡1=115°
the answer is
m∡1=115°
For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer:

Step-by-step explanation:
we have

we know that

substitute

Factor 2
![2[(2)x+(7)]](https://tex.z-dn.net/?f=2%5B%282%29x%2B%287%29%5D)

Where what assignment are you talking about
Answer:
yes
Step-by-step explanation:
yes that is true you are correct