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mestny [16]
3 years ago
14

When a marble is dropped into a beamer of water

Chemistry
2 answers:
STatiana [176]3 years ago
7 0

The mass of the marble is greater than that of the water. The marble weighs more than an equivalent volume of the water. The force from dropping the marble breaks the surface tension of the water. The marble has greater mass and volume than the water.

nika2105 [10]3 years ago
5 0

Answer:

<h2>The water will rise. </h2>

Explanation:

hope this helps you

<h2>-Sweety<3</h2>
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Answer:

An atom is the basic building block of matter. Anything that has a mass-- in other words, anything that occupies space--is composed of atoms.

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What is a hypothesis?
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Answer: a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.

Explanation: definition

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What are three types of subatomic particles
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Consider the reaction: CaCO3(s) à CaO(s) + CO2(g)
Vsevolod [243]

Answer:

131.5 kJ

Explanation:

Let's consider the following reaction.

CaCO₃(s) → CaO(s) + CO₂(g)

First, we will calculate the standard enthalpy of the reaction (ΔH°).

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g) ) - 1 mol × ΔH°f(CaCO₃(s) )

ΔH° = 1 mol × (-634.9 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1207.6 kJ/mol)

ΔH° = 179.2 kJ

Then, we calculate the standard entropy of the reaction (ΔS°).

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g) ) - 1 mol × S°(CaCO₃(s) )

ΔS° = 1 mol × (38.1 J/mol.K) + 1 mol × (213.8 J/mol.K) - 1 mol × (91.7 J/mol.K)

ΔS° = 160.2 J/K = 0.1602 kJ/K

Finally, we calculate the standard Gibbs free energy of the reaction at T = 25°C = 298 K.

ΔG° = ΔH° - T × ΔS°

ΔG° = 179.2 kJ - 298 K × 0.1602 kJ/K

ΔG° = 131.5 kJ

6 0
3 years ago
Need help ASAP please!
bearhunter [10]

Answer:

13 mol NO

Explanation:

Step 1: Write the balanced equation

4 NH₃(g) + 5 O₂(g) ⇒ 4 NO(g) + 6 H₂O(g)

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to NO is 5:4.

Step 3: Calculate the number of moles of O₂ needed to produce 16 moles of NO

We will use the previously established molar ratio.

16 mol O₂ × 4 mol NO/5 mol O₂ = 13 mol NO

3 0
3 years ago
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