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3 years ago

What is the percent composition of Phosphorus in Li3PO3

Chemistry

1 answer:

Vilka [71]3 years ago

5 0

Answer:

you will get 17.983 g of lithium for every 100 g of lithium phosphate.

Explanation:

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You have 16.7 grams of hydrogen and 15.4 grams of oxygen in a synthesis rxn. Which is the limiting reagent?

sleet_krkn [62]

Answer:

oxygen is limiting reactant

Explanation:

Given data:

Mass of hydrogen = 16.7 g

Mass of oxygen = 15.4 g

Limiting reactant = ?

Solution:

Chemical equation:

2H₂ + O₂ → 2H₂O

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 16.7 g/ 2 g/mol

Number of moles = 8.35 mol

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 15.4 g/ 32 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of both reactant with product,

H₂ : H₂O

2 : 2

8.35 : 8.35

O₂ : H₂O

1 : 2

0.48 : 2×0.48 = 0.96 mol

The number of moles of water produced by oxygen are less so it will limiting reactant.

3 0

2 years ago

An earthquake's____<br> located directly above its_____

Kipish [7]

Answer:

An earthquake's <u>what happens when two blocks of the earth suddenly slip past one another. </u>

located directly above its <u>The epic Center </u>

Explanation:

<h2>Hope this helps you !! </h2>

6 0

2 years ago

A(n) ____________________ is a negatively charged subatomic particle.

gtnhenbr [62]

An electron is a negatively charged subatomic particle, whereas a proton is positively charged, and a neutron has no charge.

8 0

2 years ago

What is the specific heat for the steel wire

olganol [36]

I think that the answer is 0.49

8 0

2 years ago

The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m

monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

= 130 x $10^{-12}$ m

The diameter of a vanadium atom = 2 x radius

= 2 x 130 x $10^{-12}$

= 260 x $10^{-12}$ m

Given a distance of 1.30 mm = 1.30 x $10^{-3}$ m,

The number of vanadium atoms required to span the distance = $\frac{1.3*10^{-3} }{260*10^{-12} }$

= 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

3 0

2 years ago