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3 years ago

If angle ABE = 2n + 7 and angle EBF=4n-13,find angle ABE.

Chemistry

1 answer:

andreev551 [17]3 years ago

4 0

Answer:

The measure of angle ABE is 27°.

Explanation:

Consider the below figure attached with this question.

Given information: ∠ABE=2n+7 and ∠EBF=4n-13.

From the below figure it is clear that ∠ABE and ∠EBF are congruent.

$m\angle ABE=m\angle EBF$

$2n+7=4n-13$

Isolate variable terms on one side.

$7+13=4n-2n$

$20=2n$

Divide both sides by 2.

$10=n$

The value of n is 10.

We need to find the measure of ∠ABE.

$\angle ABE=2(10)+7=20+7=27$

Therefore, the measure of angle ABE is 27°.

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3 years ago

Chlorine pentafluoride gas is collected at -17.0 °C in an evacuated flask with measured volume of 35.0 L. When all the gas has b

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Answer:

1. The mass of Chlorine pentafluoride, ClF5, is 39.16g

2. The number of mole of Chlorine pentafluoride, ClF5, is 0.3mole

Explanation:

1. To solve the mass of Chlorine pentafluoride, ClF5, first, let us calculate the molar mass of ClF5. This is illustrated below:

Molar Mass of ClF5 = 35.5 + (5 x 19) = 35.5 + 95 = 130.5g/mol

From the ideal gas equation:

PV = nRT (1)

Recall:

Number of mole(n) = mass (m) /Molar Mass(M)

n = m/M

Now substituting the value of n in equation 1, we have:

PV = nRT

PV = mRT/M

Now we can obtain the mass of Chlorine pentafluoride ClF5 as follow:

Data obtained from the question include:

T (temperature) = -17.0 °C = - 17 + 273 = 256K

V (volume) = 35L

P (pressure) = 0.180 atm

R (gas constant) = 0.082atm.L/Kmol

m (mass of Chlorine pentafluoride) =?

M (molar mass of Chlorine pentafluoride) = 130.5g/mol

PV = mRT/M

0.180 x 35 = m x 0.082 x 256/ 130.5

Cross multiply to express in linear form as shown below:

m x 0.082 x 256 = 0.180x35x130.5

Divide both side by 0.082 x 256

m = (0.180x35x130.5) /(0.082x256)

m = 39.16g

Therefore, the mass of Chlorine pentafluoride, ClF5, is 39.16g

2. The number of mole of ClF5 can be obtained as follow:

Mass of ClF5 = 39.16g

Molar Mass of ClF5 = 130.5g/mol

Mole of ClF5 =?

Number of mole = Mass /Molar Mass

Mole of ClF5 = 39.16/130.5g

Mole of ClF5 = 0.3mole

8 0

3 years ago

Read 2 more answers

If angle ABE = 2n + 7 and angle EBF=4n-13,find angle ABE.​

If angle ABE = 2n + 7 and angle EBF=4n-13,find angle ABE.