![\bf \begin{array}{lllll} round(x)&\boxed{1}&2&3&\boxed{4}\\\\ wrestlers[f(x)]&\boxed{64}&32&18&\boxed{9} \end{array} \\\\\\ slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby \begin{array}{llll} average\ rate\\ of\ change \end{array}\\\\ -------------------------------\\\\ f(x)= \qquad \begin{cases} x_1=1\\ x_2=4 \end{cases}\implies \cfrac{f(4)-f(1)}{4-1}\implies \cfrac{9-64}{4-1}\implies \cfrac{-55}{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blllll%7D%0Around%28x%29%26%5Cboxed%7B1%7D%262%263%26%5Cboxed%7B4%7D%5C%5C%5C%5C%0Awrestlers%5Bf%28x%29%5D%26%5Cboxed%7B64%7D%2632%2618%26%5Cboxed%7B9%7D%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0Aslope%20%3D%20%7B%7B%20m%7D%7D%3D%20%5Ccfrac%7Brise%7D%7Brun%7D%20%5Cimplies%20%0A%5Ccfrac%7B%7B%7B%20f%28x_2%29%7D%7D-%7B%7B%20f%28x_1%29%7D%7D%7D%7B%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%7D%5Cimpliedby%20%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Aaverage%5C%20rate%5C%5C%0Aof%5C%20change%0A%5Cend%7Barray%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0Af%28x%29%3D%20%20%20%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ax_1%3D1%5C%5C%0Ax_2%3D4%0A%5Cend%7Bcases%7D%5Cimplies%20%5Ccfrac%7Bf%284%29-f%281%29%7D%7B4-1%7D%5Cimplies%20%5Ccfrac%7B9-64%7D%7B4-1%7D%5Cimplies%20%5Ccfrac%7B-55%7D%7B3%7D)
55 over 3, or 55 wrestlers for every 3 rounds, but the wrestlers value is negative, thus 55 "less" wrestlers for every 3 rounds on average.
Answer:
8.2 *10^5 ft lb
Step-by-step explanation:
Wcoal = 800*500 = 400000 = 4*10^5 ft lb

Using a right Riemann sum
The width of the entire region to be estimated = 400 - 0 = 400
Considering 8 equal subdivisions, then the width of each rectangular division is 400/8 = 50
F(x) = 6(400-y)
![\left[\begin{array}{cccccccccc}x&0&50&100&150&200&250&300&350 &400\\f(x)&2400&2100&1800&1500&1200&900&600&300&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccccccccc%7Dx%260%2650%26100%26150%26200%26250%26300%26350%20%26400%5C%5Cf%28x%29%262400%262100%261800%261500%261200%26900%26600%26300%260%5Cend%7Barray%7D%5Cright%5D)
Wrope = 50(2100) + 50(1800) + 50(1500) + 50(1200) + 50(900) + 50(600)
+ 50(300) + 50(0) = 420000 = 4.2 * 10^5 ft lb
Note: Riemann sum is an approximation, so may not give a accurate value
work done = Wcoal + Wrope= 4*10^5+ 4.2 * 10^5 = 8.2 *10^5 ft lb
Answer:
Olga's mistake: She did not multiply
and
in the beginning
Step-by-step explanation:
The main problem is that when a number is outside of the parentheses on the left side, then you have to multiply that number, in this case
, by both numbers in the parentheses. After that, continue solving the problem as you usually would. Hope this helped!
Answer:
45%
Step-by-step explanation:
816 divided by 1,810 is .45
I was looking into it and found 41.3