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3 years ago

Which of the following modifications to the list of assets and liabilities below would result in a positive net worth?

Mathematics

1 answer:

tatuchka [14]3 years ago

8 0

Answer:

the assets and liabilities are even right now, so a net worth of zero.

so, D. all of the above

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Let f(x) = cos(x) + 2x. Where does f have critical points?

adell [148]

Answer:

f has no critical points.

Step-by-step explanation:

We are given:

$f(x)=\cos(x)+2x$

A function has critical points whenever its derivative equals 0 or is undefined.

Differentiate the function:

$f'(x)=-\sin(x)+2$

Since this will never be undefined, solve for its zeros:

$0=-\sin(x)+2$

Hence:

$\displaystyle \sin(x)=2$

Recall that the value of sine is always between -1 and 1.

Thus, no real solutions exist.

Therefore, f has no critical points.

6 0

3 years ago

Which of the following functions has a domain of LaTeX: \left[2,7\right][ 2 , 7 ] and a range of LaTeX: \left[4,9\right][ 4 , 9

irina1246 [14]

Dbdndndndndndbbdbdbdbddbbdbdbdbdb

6 0

3 years ago

Tim needs to use one kilogram of pasta to serve four persons. How many grams of pasta do they each have?

bogdanovich [222]

Answer: 250 grams

Explanation: A kilogram is equal to 1000 grams. All you have to do is divide the 1000 between the 4 people.
1000/4=250

5 0

2 years ago

Last three digit of cube of 500 is 0

Shkiper50 [21]

Answer:

true

Step-by-step explanation:

7 0

3 years ago

The population of a certain country in 1997 was 288 million people. In addition, the population of the country was growing at a

Crazy boy [7]

Answer:

a) In the year 1998 with 3 days, 2 hours, 44 minutes and 18.1006141 seconds

b) In the year 1998 with 19 days, 18 hours, 5 minutes and 35.10875472 seconds

Step-by-step explanation:

a) To know the time when the population will be 305 million people, we need to isolate the variable t in the equation, $P(t)=288(1.009)^{t-1997}$

So we isolate t with the property of logarithms that allow us go down the exponent, applying in both sides of the equation

For this subsection the value of P is equal to 305 million people

$Ln(305)=Ln[(288)(1.009)]^{t-1997}$

$Ln(305)=(t-1997)*Ln[(288)(1.009)]$

Now, we can isolate the value of t

$\frac{Ln(305)}{Ln[(288)(1.009)]} =t-1997$

$\frac{Ln(305)}{Ln[(288)(1.009)]}-1997 =t$

$t=1998.008531776402$

So to know the exact date we multiply the number after the point, that is 0.008531776402 for the number of days that have 1 year, equal to 365 days

0.008531776402*365= 3.114098387 days

then the number after the point, that is 0.114098387 will be multiply for the number of hours that have 1 day

0.114098387*24= 2.738361282 hours

then the number after the point, that is 0.738361282 will be multiply for the number of minutes that have 1 hour

0.738361282*60= 44.3016769 minutes

Finally, the number after the point, that is 0.3016769 will be multiply for the number of seconds that have 1 minute

0.3016769*60= 18.1006141 seconds

And we obtain that the time, when the population of the country is 305 million people, is in the year 1998 with 3 days, 2 hours, 44 minutes and 25.152 seconds

b) For calculate the time when the population is 395 million people, we do the same process we did in the subsection a)

$Ln(395)=Ln[(288)(1.009)]^{t-1997}$

$Ln(395)=(t-1997)*Ln[(288)(1.009)]$

Now, we can isolate the value of t

$\frac{Ln(395)}{Ln[(288)(1.009)]} =t-1997$

$\frac{Ln(395)}{Ln[(288)(1.009)]}-1997 =t$

$t=1998.05412021527$

0.05412021527*365= 19.75387857 days

0.75387857 *24= 18.09308577 hours

0.09308577*60= 5.585145912 minutes

0.585145912*60= 35.10875472 seconds

And we obtain that the time, when the population of the country is 395 million people, is in the year 1998 with 19 days, 18 hours, 5 minutes and 35.10875472 seconds

8 0

3 years ago