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Temka [501]
4 years ago
10

You and your friend are rolling number cubes. Each cube has 6 sides with the numbers 1 to 6. If a sum of 7 is rolled, your frien

d gets a point. However, you get a point if either one of the sums listed below is rolled. Which pair of numbers would make the game fair?
2 and 12
2 and 5
12 and 8
Mathematics
1 answer:
kherson [118]4 years ago
5 0
Sum ---- Combinations
2 --------- 1
3 --------- 2
4 --------- 3
5 --------- 4
6 --------- 5
7 --------- 6
8 --------- 5
9 --------- 4
10 ------- 3
11 ------- 2
12 ------- 1

7 has 6 combinations.
Now,
2 and 12 ---- 1+1 = 2
2 and 5 ------1+4 = 5
12 and 8 ---- 1+5 = 6

12 and 8 would, therefore, make the game fair.
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What is the solution of StartRoot x squared + 49 EndRoot = x + 5?
Natasha2012 [34]

x=\frac{12}{5} or x= twelve-fifths

Option A is correct.

Step-by-step explanation:

We need to find the solution of:

\sqrt{x^2+49}=x+5

Solving:

Taking square on both sides:

(\sqrt{x^2+49})^2=(x+5)^2\\x^2+49=x^2+2(x)(5)+25\\Simplifying:\\x^2+49-x^2-10x-25=0\\-10x+24=0\\-10x=-24\\x=\frac{-24}{-10}\\ x=\frac{24}{10}\\x=\frac{12}{5}

Verifying the solution by putting x = 12/5 in the given equation, we get true result.

So, x=\frac{12}{5} or x= twelve-fifths

Option A is correct.

Keywords: Solving Square root Equations

Learn more about Solving Square root Equations at:

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  • brainly.com/question/10666510

#learnwithBrainly

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The answer is B.


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4 years ago
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