1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dalvyx [7]
2 years ago
5

What is the common denominator of 7/8 and 5/6

Mathematics
2 answers:
igor_vitrenko [27]2 years ago
8 0

Answer:

24

Step-by-step explanation:

7/8 = 7/8 × 3/3 = 21/24

5/6 = 5/6 × 4/4 = 20/24

For the denominators (8, 6) the least common multiple (LCM) is 24.

Andrej [43]2 years ago
7 0

Answer:

2

Step-by-step explanation:

2 x 4 = 8

2 x 3 = 6

You might be interested in
Armando has collection of 25 coins . Of the 25 coins , 11 are nickles. What percent of the coins are nickles ?
Marysya12 [62]

Answer:

10%

Step-by-step explanation:

3 0
3 years ago
Two figures are similar with a scale factor of 5/2.
aev [14]

Answer:

If we have two figures, F and F'

Such that if we start with F, and dilate it with a scale factor K, we get F'.

We will have:

All the measures of F', are K times the correspondent measures of F.

Then if F has  s₁, s₂, ..., sₙ sides, the sides of F' will be:

K*s₁, K*s₂, ..., K*sₙ

The ratio between correspondent sides will be equal to K

The ratio between perimeters will also be equal to K (because the perimeter is the sum of all the sides of each figure, so we can just take K as a common factor)

In the case of the area, because we usually multiply a measure by another, a factor K^2 will  appear, and the quotient between the areas is K^2

And finally, for the volumes, the ratio will be K^3

a) The ratio of corresponding lengths is K, in this case is 5/2

b) The ratio of the perimeters is K, in this case is 5/2

c) The ratio of the areas is K^2, in this case is (5/2)^2 = 25/4

d) The ratio of the areas is K^3, in this case is (5/2)^3 = 125/8

e) Two figures are similar if the figures have the same shape, then the corresponding angles are exactly the same, then the ratio of corresponding angle measures is 1.

6 0
3 years ago
Help me pls i need help asap​
CaHeK987 [17]

Answer:

no babe

Step-by-step explanation:

6 0
3 years ago
Plz help this question out
Elden [556K]

Answer:

bad in this..............

3 0
2 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
Other questions:
  • I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT
    7·1 answer
  • PLEASE HELP ON THIS! ILL GIVE BRAINLY AND 50 POINTS!
    14·2 answers
  • In the right triangle shown, the third side can be represented by the expression
    7·1 answer
  • Angela earns $6.25 per hour babysitting. Estimate how much she will earn if she babysits for 9 hours this weekend. Explain.
    10·1 answer
  • I need help with 7. Please show me how u got to your answer and please do the explanations
    12·1 answer
  • Estimate the answer to the<br> calculation below<br> 21 X 385<br> 52
    11·1 answer
  • Determine the answer to (−3) + (−5) and explain the steps using a number line
    15·1 answer
  • What is a possible solution to x ≥ −2?
    10·1 answer
  • ILL GIVE BRAINIEST IF U GET IT RIGHT Sarah has red and blue modeling clay. When she found that of her modeling clay was red, she
    15·1 answer
  • Wath is 12.50/3 <br> cuz i need
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!