The trick with this problem is that there is no trick - there's no math involved at all, just wordplay. The key is in one-time deposit; what you're looking for isn't a recurring fee, but rather a constant. Now, an equation is made up of three things:
- a variable
- a relational statement in the form of =
- a constant, even if it isn't really there, it's zero
In this case, what you're looking for is the constant in the equation; a value that doesn't change when any variable changes.
The only number in your question that fits the bill is 1200$, since it's a <em>one-time, unchanging value.</em> <em>y </em>is the total amount paid and x represents the months, which are both variables; 400 is tied to x, so it also changes based on months.
6x8=
{6x 4} + {6x 4 }
= + =
24 24
48
68x87 i think?
sorry if that isnt right..
Answer:
Step-by-step explanation:
leg1² + leg2² = hypotenuse²
AC² + BC² = AB²
2² + 5² = c²
Let U = {1, 2, 3, 4, 5, 6, 7}, A= {1, 3, 4, 6}, and B= {3, 5, 6}. Find the set A’ U B’
Art [367]
Answer:
Step-by-step explanation:
A'={2,5,7}
B'={1,2,4,7}
A'UB'={1,2,4,5,7}
