First you do -3bk+9bk and that equals 6bk then since there are no more like terms the experssion would be simplified into 6bk+2-6b
HOPE THAT HELPED!
Using the probability and odds concepts, it is found that the odds against it containing a number greater than or equal to 7 is
.
- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
- An odd is the <u>number of desired outcomes divided by the number of non-desired outcomes</u>.
In the rack, there are 15 balls, numbered from 1 to 15. Of those, <u>6 are less than 7</u>(against it containing a number greater than or equal to 7 is equivalent to it containing a number less than 7), thus:
- There are 6 desired outcomes.
- There are 9 non-desired outcomes.
The odd is:

The odds against it containing a number greater than or equal to 7 is
.
A similar problem is given at brainly.com/question/21094006
Answer:
Perimeter: 4 * s
Area: S 2
Diagonal: s 2 \sqrt {2} 2
Area of square when diagonal is given = 1 2 × d 2 \frac {1} {2}\times d^ {2} 21 × d2
Step-by-step explanation:
Where’s the triangle, isn’t there supposed to be a picture with the question
Answer:
images are:
W'(-5,0)
X'(0,-9)
Y'(-9,-6)
Z'(-6,-2)
Step-by-step explanation:
use formula p(x,y)=p'(y,-x)