Answer: Temperature of one liter of phosphine gas with a mass of 1.725 g and gas pressure of 0.9910 atm is 
Explanation:
According to the ideal gas equation:
PV=nRT
P = Pressure of the gas = 0.9910 atm
V= Volume of the gas= 1.0 L
T= Temperature of the gas in kelvin = ?
R= Gas constant =
n= moles of gas= 


Thus the temperature (in °C) of one liter of phosphine gas with a mass of 1.725 g and gas pressure of 0.9910 atm is 
Molar mass
HNO₃ = 63.02 g/mol
N₂O = 44.013 g/mol
The balanced equation is :
<span>4 Zn + 10 HNO₃ = 4 Zn(NO₃)₂ + N₂O + 5 H₂O
</span>
10 * 63.02 g HNO₃-----------> 44.013 g N₂O
? HNO₃ -----------------> 8.75 g N₂O
Mass HNO₃ = 8.75 * 10 * 63.02 / 44.013
Mass HNO₃ = 125 g
hope this helps!
Rate, fast :Maybe these are the answers.
It is not equal because it dose not obey the conservation of mass. 60+25= 85 not 75.