Always use this method !!! always
Answer:
Hydrogen bromide, anhydrous appears as a colorless gas with a pungent irritating odor. Corrosive. Heavier than air. Prolonged exposure to fire or intense heat may result in the violent rupture and rocketing of the container. Long-term exposure to low concentrations or short-term exposure to high concentrations can result in adverse health effects from inhalation. Used to make other chemicals and as a catalyst in the manufacture of chemicals. Rate of onset: Immediate Persistence: Minutes to hours Odor threshold: 2 ppm Source/use/other hazard: Chemical manufacturing industry; very corrosive.
Explanation:
HBr
Answer:
Explanation:
Formula
Heat = m * c * delta t
t = temperature in centigrade.
The first thing you have to do is convert kelvin degrees to centigrade. The conversion factor is - 273. The formula is degrees centigrade = degrees kelvin - 273. It is easier to understand with a couple of examples.
- 290o K = 290 - 273 = 17
- 325. K = 325 - 273 = 52
Solution
Heat = 100.0 grams * 4.18 J/g*C * (52 - 17)
Heat = 100 * 4.18 * 35
Heat = 14630 Joules
But you want kj
Heat = 14630 / 100 = 14.63
Answer
Heat = 14.6 kj
Answer:
oxygen is limiting reactant
Explanation:
Given data:
Mass of phosphorus = 25.0 g
Mass of oxygen = 50.0 g
What is limiting reactant ?
Solution:
Chemical equation:
P₄ + 5O₂ → P₄O₁₀
Number of moles of P₄:
Number of moles = mass/molar mass
Number of moles = 25.0 g/ 123.89 g/mol
Number of moles = 0.20 mol
Number of moles of O₂:
Number of moles = mass/molar mass
Number of moles = 50.0 g/ 32 g/mol
Number of moles = 1.56 mol
now we will compare the moles of reactants with product:
P₄ : P₄O₁₀
1 : 1
0.20 : 0.20
O₂ : P₄O₁₀
5 : 1
1.56 : 1/5×1.56 = 0.312 mol
Less number of moles of product are formed by the oxygen thus it will act as limiting reactant.
Answer:
1.35 m
Explanation:
We can solve this problem by using the <em>freezing point depression formula</em>:
Where:
- ΔT is the temperature difference between the freezing point of the pure solvent (water) and the solution. In this case it is (<em>0 °C - -2.5 °C = 2.5 °C</em>).
- Kf is the cryoscopic constant, <em>for water it is 1.853 °C*kg/mol.</em>
- i is the van't Hoff factor, <em>as sugar does not dissociate in water, it has a value of 1</em>.
We <u>input the data</u>:
- 2.5 °C = 1.853 °C*kg/mol * m * 1
And <u>solve for m</u>:
