Answer:
pH>7
sour taste
donate H+ ions
turn litmus paper from blue to red
Explanation:
There are 3.01 moles. round to 3 if it asks for a whole number
Answer:
D. 91.0%
Explanation:
Hello,
In this case, for the given chemical reaction:
![Na_2S+2AgNO_3 \rightarrow Ag_2S + 2NaNO_3](https://tex.z-dn.net/?f=Na_2S%2B2AgNO_3%20%5Crightarrow%20Ag_2S%20%2B%202NaNO_3)
Next, since silver nitrate (molar mass 169.87 g/mol) is in a 2:1 molar ratio with silver sulfide (molar mass 247.8 g/mol), we compute its theoretical yield as shown below:
![m_{Ag_2S}^{theoretical}=4.27gAgNO_3*\frac{1molAgNO_3}{169.87gAgNO_3} *\frac{1molAg_2S}{2molAgNO_3}*\frac{247.8gAg_2S}{1molAg_2S}\\\\m_{Ag_2S}^{theoretical}=3.11gAg_2S](https://tex.z-dn.net/?f=m_%7BAg_2S%7D%5E%7Btheoretical%7D%3D4.27gAgNO_3%2A%5Cfrac%7B1molAgNO_3%7D%7B169.87gAgNO_3%7D%20%2A%5Cfrac%7B1molAg_2S%7D%7B2molAgNO_3%7D%2A%5Cfrac%7B247.8gAg_2S%7D%7B1molAg_2S%7D%5C%5C%5C%5Cm_%7BAg_2S%7D%5E%7Btheoretical%7D%3D3.11gAg_2S)
Next, we compute the percent yield as:
![Y=\frac{m_{Ag_2S}^{actual}}{m_{Ag_2S}^{theoretical}}*100\% =\frac{2.86g}{3.11g} *100\%\\\\Y=91.0%](https://tex.z-dn.net/?f=Y%3D%5Cfrac%7Bm_%7BAg_2S%7D%5E%7Bactual%7D%7D%7Bm_%7BAg_2S%7D%5E%7Btheoretical%7D%7D%2A100%5C%25%20%3D%5Cfrac%7B2.86g%7D%7B3.11g%7D%20%2A100%5C%25%5C%5C%5C%5CY%3D91.0%25)
Hence, answer is D. 91.0%.
Best regards.
Solubility at 100 °C = 480 g / 100 mL of solution =: saturated solution
The proportion 240 g / 50 mL is equal to the saturated ratio 480 g / 100 mL
Then, 240 g of sugar in 50 mL of boiling water will make a saturated solution.
Answer: saturated
<span>(2) butynu........................</span>