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2 years ago

1 point

Chemistry

1 answer:

lawyer [7]2 years ago

6 0

Answer:

Explanation:

you're moving the decimal 8 spots to the left so it can only be B

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A radioactive isotope of potassium (K) has a half-life of 20 minutes. If a 40.0 gram sample of this isotope is allowed to decay

Ivahew [28]

Answer: 2.5 grams

Explanation:

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3 years ago

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How many total phosphorus atoms are shown in the following: Al2P3? *

Wewaii [24]

Answer:

3 P atoms

Explanation:

Al₂P₃ => contains 2 Aluminum ions (2Al⁺³) and 3 Phosphide ions (3P⁻³) ... The ions (charged particles) are from atoms that have lost or gained electrons during the bonding process. So, Al₂P₃ => P⁻³ ions from 3 P atoms.

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3 years ago

Nickel carbonyl, Ni(CO)4 is one of the most toxic substances known. The present maximum allowable concentration in laboratory ai

vodomira [7]

Answer: The mass of $Ni(CO)_4$ allowable in the laboratory is 4599.5 grams

Explanation:

To calculate the volume of cuboid, we use the equation:

$V=l\times b\times h$

where,

V = volume of cuboid

l = length of cuboid = 14 ft

b = breadth of cuboid = 22 ft

h = height of cuboid = 9 ft

Putting values in above equation, we get:

$V=14\times 22\times 9=2772ft^3=78503.04L$ (Conversion factor: $1ft^3=28.32L$

To calculate the moles of gas, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = 78503.04 L

T = Temperature of the gas = $23^oC=[23+273]K=296K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles of hydrogen gas = ?

Putting values in above equation, we get:

$1.00atm\times 78503.04L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 296K\\\\n=\frac{1.00\times 78503.04}{0.0821\times 296}=3230.4mol$

Applying unitary method:

For every 109 moles of gas, the moles of $Ni(CO)_4$ present are 1 moles

So, for 3230.4 moles of gas, the moles of $Ni(CO)_4$ present will be = $\frac{1}{109}\times 3230.4=26.94mol$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of $Ni(CO)_4$ = 26.94 moles

Molar mass of $Ni(CO)_4$ = 170.73 g/mol

Putting values in above equation, we get:

$26.94mol=\frac{\text{Mass of }Ni(CO)_4}{170.73g/mol}\\\\\text{Mass of }Ni(CO)_4=(26.94mol\times 170.73g/mol)=4599.5g$

Hence, the mass of $Ni(CO)_4$ allowable in the laboratory is 4599.5 grams

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3 years ago

How to calculate the limiting reatant

artcher [175]

1. Determine the balanced chemical equation for the chemical reaction
2. Convert all given information into moles ( most likely, through the use of molar mass as a conversion factor).
3. Calculate the mole ratio from the given information.

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3 years ago

What is bonding pair

slavikrds [6]

Bond pair is simply a pair of electron which is being shared mutually between two atoms forming a chemical bond or in other words, it means the electron density lies in between two atoms.

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