Answer:
5
Step-by-step explanation:
The nth term of a geometric series is:
a_n = a₁ (r)^(n-1)
where a₁ is the first term and r is the common ratio.
Here, we have:
40 = a₁ (r)^(4-1)
160 = a₁ (r)^(6-1)
40 = a₁ (r)^3
160 = a₁ (r)^5
If we divide the two equations:
4 = r^2
r = 2
Now substitute into either equation to find a₁:
40 = a₁ (2)^3
40 = 8 a₁
a₁ = 5
Answer: option A. 25.
Explanation:
1) f [g (1) ] ⇒ find the image of g(1) and use it as the input for f(x).
2) g(x) = 5 => g(1) = 5
3) f (g (1) ) = f (5) = (5)² = 25
That is the answer: f [ g(1) ] = 25.
Answer:
4w.
Step-by-step explanation:
Replace w with 9.
7(9)=63
4(9)=36
6(9)=54
5(9)=45
Therefore the answer is 4w.
Because angleCBD+angleBDC+angleC=180
so angleCBD+angleBDC=180-angleC=180-82=98
because BC=DC
so angleCBD=angleBDC
so 2 angleCDB=98
so angleCDB=49
so y=29
by Joy Xu,紫馨雪汐
Answer:
<u>The next two terms for the geometric sequence are - 108 and - 324.</u>
Step-by-step explanation:
1. Let's find the next two terms for the geometric sequence which first three terms are as follows:
- 4, 12, - 36.....
Aₓ = Aₓ₋₁ * 3 ; A₁ = - 4
A₁ = - 4
A₂ = A₁ * 3 = - 4 * 3 = - 12
A₃ = A₂ * 3 = - 12 * 3 = - 36
A₄ = A₃ * 3 = - 36 * 3 = - 108
A₅ = A₄ * 3 = - 108 * 3 = - 324
<u>The next two terms for the geometric sequence are - 108 and - 324.</u>