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yanalaym [24]
2 years ago
12

All of the following are true of betas and correlation coefficients EXCEPT: Group of answer choices Both betas and correlation c

oefficients can tell you something about the strength of a relationship. Betas describe the relationship between two variables exactly as correlations coefficients do. Betas from an analysis can be compared with other beta coefficients from the same analysis just as correlation coefficients can. Both betas and correlation coefficients can tell you something about the direction of a relationship.
Mathematics
1 answer:
fgiga [73]2 years ago
8 0

Answer:

yes look at the eslotp uudh

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Angles relationships
amm1812

2x = 74

x = 74 ÷ 2

x = 37

that's all

7 0
3 years ago
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Aliyah I had some candy to give to her four children. she first took ten pieces for herself and then evenly divided the rest amo
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She started with 18 prices of candy
4 0
3 years ago
Minor surgery on horses under field conditions requires a reliable short-term anesthetic producing good muscle relaxation, minim
iren [92.7K]

Answer:

We accept  H₀

Step-by-step explanation:

Normal Distribution

size sample   n  = 69

sample mean  18.94

standard deviation  8.3

Is a one tailed-test to the left we are traying of find out is we have enough evidence to say that the mean is less than 20 min.

1.-Test hypothesis                              H₀         ⇒   μ₀  =  20

   Alternative hypothesis                  Hₐ         ⇒    μ₀  < 20

2.- Critical value

for α = 0.1  we find from z Table

z(c) = - 1.28

3.-We compute z(s)

z(s) = [ (  μ  -  μ₀ ) / (σ/√n)                ⇒    z(s) = [( 18.94  -  20  )*√69)/8.3]

z(s) = ( -1.06)*8.31/8.3                    

z(s) =  - 1.061

4.- We compare

z(c)   and z(s)           -1.28 > -1.061

Then z(c)    >  z(s)

z(s) in inside acceptance region  so we accept H₀

5 0
3 years ago
(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

6 0
3 years ago
Find an equation of the line with the given slope and​ y-intercept.
vlabodo [156]

Answer:

y=-2x-13

Step-by-step explanation:

y-y1=m(x-x1)

y-(-13)=-2(x-0)

y+13=-2x

y=-2x-13

3 0
3 years ago
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