3 years ago

The least penetrating form of radiation is

Physics

2 answers:

goldfiish [28.3K]3 years ago

6 0

Answer:

radio radiation........

wolverine [178]3 years ago

3 0

Answer

C.( Alpha particles!

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What is the gauge pressure (in atm) in a 25.0°C car tire containing 3.81 mol of gas in a 31.5 L volume? (Enter your answer to at

bagirrra123 [75]

Answer:

Explanation:

Given

Temperature of gas $T=25^{\circ}C\approx 298\ K$

Volume of gas $V=31.5\ L\approx 31.5\times 10^{-3}\ m^3$

no of moles of gas $n=3.81\ mol$

Using Ideal gas Equation to find the Pressure of gas

$PV=nRT$

where P=Absolute Pressure

V=Volume

R=Universal gas constant

T=Temperature

$P\times 31.5\times 10^{-3}=3.81\times 8.314\times 298$

$P=\frac{3.81\times 8.314\times 298}{31.5\times 10^{-3}}$

$P=299.66\ kPa$

And we know Atmospheric Pressure is $101.325\ kPa$

Therefore Gauge pressure is given by

$P_{gauge}=P-P_{atm}$

$P_{gauge}=299.66-101.325$

$P=198.34\ kPa$

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3 years ago

at what position an object be placed in front of a concave mirror of radius of curvature 40cm so that an erect image of magnific

Thepotemich [5.8K]

C=40cm
f=C/2=40/2=20

$\\ \sf\longmapsto m=\dfrac{f}{f-u}$

$\\ \sf\longmapsto 3=\dfrac{20}{20-u}$

$\\ \sf\longmapsto 3(20-u)=20$

$\\ \sf\longmapsto 60-3u=20$

$\\ \sf\longmapsto 3u=40$

$\\ \sf\longmapsto u=13.3cm$

m=magnification
f is focal length
C is radius of curvature
u is object distance

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3 years ago

A plane initially traveling at 200 m/s due west experiences a 10 m/s head wind coming from the opposite direction. A). What will

Hitman42 [59]

Ok so it would be late and the relative velocity would be 190 m/s because 200 m/s - 10 m/s is 190 m/s. Hope this helps.

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4 years ago

Which statement is true if the mass of object A is twice that of object B?

Contact [7]

Answer:

b is the answer

Explanation:

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3 years ago

A bullet is fired through a board 13.0 cm thick in such a way that the bullet's line of motion is perpendicular to the face of t

GREYUIT [131]

Answer:

392307.6923 m/s²

Explanation:

t = Time taken

u = Initial velocity = 560 m/s

v = Final velocity = 460 m/s

s = Displacement = 13 cm

a = Acceleration

From the equation of motion we have

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{460^2-560^2}{2\times 13\times 10^{-2}}\\\Rightarrow a=-392307.6923\ m/s^2$

The acceleration of the bullet as it passes through the board is -392307.6923 m/s²

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3 years ago