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Ymorist [56]
2 years ago
9

What does the area under the velocity-time graph represent.

Physics
1 answer:
V125BC [204]2 years ago
8 0

Answer:

The distance traveled!

Explanation:

This is a velocity time graph of an object moving in a straight line due North.

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If you were to mix 3 liters of 20 degrees celsius water with 4 liters of 30 degrees water at 7 liters of water what temperature
Debora [2.8K]
Lets say final temperature is @ celsius
3c(@-20)= 4c([email protected])
[email protected]=180
@=180/7
3 0
3 years ago
friction between the tire of a moving car and the dry pavement is: A. static B. rolling C. sliding D. riding
qwelly [4]

Answer:A static

Explanation:

6 0
2 years ago
PLEASE HELP I'M LOST.
Zina [86]
A - 3
B - 1
C - 2
D - 4
E - 5
6 0
2 years ago
A car stands from rest and attains a speed of 20 m/s in 10 s. What distance will it cover ?​
sashaice [31]

Answer:

100m

Explanation:

100m

s=ut+1/2at^2

s= unknown, u=0, a=2, t=10

s=0*10+1/2(2)(10)^2

s=1/2(2)(100)

s=1(100)

displacement = 100 meters

4 0
3 years ago
Ethyl alcohol has a boiling point of 78.0°C, a freezing point of −114°C, a heat of vaporization of 879 kJ/kg, a heat of fusion o
Ganezh [65]

Answer:

874.2 KJ

Explanation:

Ethyl alcohol boiling point = 78oC, freezing point = -114oC heat of vaporization = 879 kJ/kg heat of fusion = 109kJ/Kg specific heat capacity (c) of ethyl alcohol = 2,43KJ/Kg.k

calculating each heat drawn singly

Quantity loss due vaporization = m × Lv where m is mass in kg and Lv is the heat of vaporization

Quantity of heat loss due to fusion = m × Lf ( heat of fusion)

Quantity of heat loss due to cooling from 78oc to -114 = m × c × ΔT 9 (change in Temperature)

Quantity of heat removed due to vaporization = 0.601 ×879 = 528.279 KJ

Quantity of heat lost due to cooling from 78oc to -114oc = mcΔT= 0.601 × 2.43 × ( 78 - (-114)) = 0.601 ×2.43 × 192 = 280.4 kJ

Quantity of heat lost due to fusion during freezing = 0.601 × 109 = 65.509 KJ

Total heat removed = sum of the each quantity of heat removed from the gaseous ethyl alcohol = 528.279 + 280.4 + 65.509 =  874.2 KJ

6 0
3 years ago
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