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alexgriva [62]
3 years ago
6

What is the equation of the inverse of g(x)=2/5x -1

Mathematics
1 answer:
garri49 [273]3 years ago
4 0

to find the inverse  interchange x and y and then solve for y

y = 2/5 x-1

x = 2/5 y-1

add 1 to each side

x+1 = 2/5 y

multiply by 5/2

5/2(x+1) =y


this is the inverse

g^-1(x) = 5/2(x+1)

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Can someone help me do part two please? It’s very important send a picture or something. I don’t even care if you tell me the st
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<h3>Explanation:</h3>

1. "Create your own circle on a complex plane."

The equation of a circle in the complex plane can be written a number of ways. For center c (a complex number) and radius r (a positive real number), one formula is ...

  |z-c| = r

If we let c = 2+i and r = 5, the equation becomes ...

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2. "Choose two end points of a diameter to prove the diameter and radius of the circle."

We don't know what "prove the diameter and radius" means. We can show that the chosen end points z₁ and z₂ are 10 units apart, and their midpoint is the center of the circle c.

For the end points of a diameter, we choose ...

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The midpoint of these two point should be the center of the circle.

  (z₁ +z₂)/2 = ((5 -1) +(5 -3)i)/2 = (4 +2i)/2 = 2 +i

  (z₁ +z₂)/2 = c . . . . . the center of the circle is the midpoint of the diameter

__₁₂₃₄

3. "Show how to determine the center of the circle."

As with any circle, the center is the <em>midpoint of any diameter</em> (demonstrated in question 2). It is also the point of intersection of the perpendicular bisectors of any chords, and it is equidistant from any points on the circle.

Any of these relations can be used to find the circle center, depending on the information you start with.

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Using this point and the z₁ and z₂ above, we can write three equations in the "unknown" circle center (a +bi):

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