To solve that question we can think by the following way:
- The first letter can be any of the letters (A, C, T or G). Therefore there are 4 possibilites.
- To choose the second letter of the sequence, any letter also can be chose. So, one more time, there are 4 possibilites.
Using the fundamental principle of counting, we will find out that can be formed differents sequences (for example, AA, AG, TT, TG, CT...).
Know we know that, we can generalize. If I have elements and I must choose one of them times to do a sequence, the total number of sequence that I can form will be .
In our question, we want to know how many DNA sequence are exactly 29 letters long. As indicated above, the answer for that is (29 times) .
Therefore, there are DNA sequences with exactly 29 letters long.
I hope I've helped you. =D
Enjoy your studies. \o/
Answer:
30
Step-by-step explanation:
6+9= 15, 15x2=30
<h3>Answer:</h3>
b. $30,675.00
<h3>Explanation:</h3>
Judging by the answer choices, the CD only earns simple interest.
The account balance at the end of 11 years will be the sum of ...
- the principal amount kept in the account the whole time: $16,500
- 11 years' interest earned on $16,500
- 3 years' interest earned on $2500 (4 years minus a 1-year penalty).
The interest amounts are ...
<em>interest on 16,500</em>
... I = Prt = 16500×0.075×11 = 13,612.50
<em>interest on 2500</em>
... I = Prt = 2500×0.075×3 = 562.50
<u><em>Total Account Value</em></u>
This is the sum listed in the bullet points above:
... account value = $16,500 +13,612.50 +562.50
... account value = $30,675.00