Question

What volume will 28 grams of nitrogen gas occupy at 27 Celsius and a pressure of 785 mm Hg?

Answer 1

Answer: $2.49\ m^3$

Explanation:

Given

Mass of nitrogen present $m=28\ g$

Temperature $T=27^{\circ}C\equiv 300\ K$

Pressure $P=785\ mm\ \text{of}\ Hg\ \text{or}\ 1.032\ atm$

The molar mass of Nitrogen $M=28\ g/mol$

No of moles of nitrogen present

$n=\dfrac{m}{M}\\\\n=\dfrac{28}{28}\\\\n=1$

Using $PV=nRT$

$\Rightarrow 1.032\times V=1\times 8.314\times 300\\\\\Rightarrow V=\dfrac{2494.2}{1.032}\\\\\Rightarrow V=2494.2\ L\ \text{or}\ 2.49\ m^3$