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uysha [10]
3 years ago
7

Identify the correct descriptions of beta particles.

Chemistry
1 answer:
FrozenT [24]3 years ago
6 0

Answer:

a. A beta particle has a negative charge. d. A beta particle is a high-energy electron.

Explanation:

Identify the correct descriptions of beta particles.

a. A beta particle has a negative charge. YES. A beta particle is originated in the following nuclear reaction: ¹₀n ⇒ ¹₁H + ⁰₋₁e (beta particle.)

b. A beta particle contains neutrons. NO. It is a electron originated in the nucleus.

c. A beta particle is less massive than a gamma ray. NO. Gamma rays don't have mass while a beta particle has a mass which is half of one thousandth of the mass of a proton.

d. A beta particle is a high-energy electron. YES. Beta particles are nuclear originated hig-energy electrons.

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Why do the elements in a group all behave similarly
Svetradugi [14.3K]

Answer:

See the explanation below, please.

Explanation:

The elements of the periodic table that belong to the same group (each column) have similar physical and chemical properties. This is because they have the same number of electrons in their last electronic layer.

Example of electronic configuration of elements of GROUP IA:

Hydrogen: 1s ^ 1

Lithium: 1s ^ 2 2s ^ 1

6 0
3 years ago
31) To extend a length of 1.00 inches, 2.54 x 10^8 average sized atoms would have to be placed in a straight line (in other word
Phoenix [80]

Answer:

Here's the conversion factor you need:

1 Kilometer   =   39370 inches

So, for your question we want to go 405,696 km....

405696 km   x   39370 inches/ 1 km  =   15972283464 inches

                       

15972283464 inches   x   2.54 x10^8 atoms/1 inch   =   4.05 x 10^18 atoms

                                     

4 0
3 years ago
Lithium has two naturally occurring isotopes, 6Li and 7Li . The atomic weight of lithium is 6.941. Which of the following statem
Mumz [18]

Answer: The abundance of Li-7 isotope is higher as compared to Li-6.

Explanation:

Average atomic mass is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

We are given:

Two isotopes of lithium :

Li-6 and Li-7

Average atomic mass of lithium= 6.941

As, the average atomic mass of lithium is closer to the mass of isotope Li-7. This means that the relative abundance of Li-7 is higher as compared to Li-6.

Percentage abundance of Li-7> Percentage abundance of Li-6 isotope

3 0
3 years ago
Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A soluti
ss7ja [257]

Answer:

1.89 of Sodium Carbonate

3.94 g of Silver Carbonate

2.43 g of Sodium Nitrate

Zero grams of Silver Nitrate

Explanation:

We have to start with the reaction:

AgNO_3~+~Na_2CO_3~->~Ag_2CO_3~+~NaNO_3

Now, we can balance the reaction:

2AgNO_3~+~Na_2CO_3~->~Ag_2CO_3~+~2NaNO_3

Now, we have to calculate the limiting reagent and we have to follow a few steps:

1) Convert to moles (using the molar mass of each compound)

2) Divide by the coefficient of each reactive (given by the balanced reaction)

<u>Convert to moles</u>

<u />

3.40~g~Na_2CO_3\frac{105.98~g~Na_2CO_3}{1~mol~Na_2CO_3}=0.032~mol~Na_2CO_3

4.86~g~AgNO_3\frac{169.8~g~AgNO_3}{1~mol~AgNO_3}=0.0286~mol~AgNO_3

<u>Divide by the coefficient</u>

<u></u>

\frac{0.032~mol~Na_2CO_3}{1}=0.032

<u />

\frac{0.0286~mol~AgNO_3}{2}=0.0143

The smallest value is for AgNO_3 , therefore the 4.86 g of AgNO_3 .

Now we can calculate the amount of compounds produced is we follow a few steps:

1) Use the molar ratio

2) Convert to moles (using the molar mass of each compound)

<u>Amount of Silver Carbonate</u>

<u />

0.0286~mol~AgNO_3\frac{1~mol~AgCO_3}{2~mol~AgNO_3}\frac{275.74~g~AgCO_3}{1~mol~AgCO_3}=3.94~g~AgCO_3

<u>Amount of Sodium Nitrate</u>

<u />

0.0286~mol~AgNO_3\frac{2~mol~NaNO_3}{2~mol~AgNO_3}\frac{84.99~g~NaNO_3}{1~mol~NaNO_3}=2.43~g~NaNO_3

<u>Amount of Sodium Carbonate (Excess reactive)</u>

<u />

0.0286~mol~AgNO_3\frac{1~mol~NaCO_3}{2~mol~AgNO_3}\frac{105.98~g~NaCO_3}{1~mol~NaCO_3}=1.51~g~NaCO_3

3.4~g~NaCO_3-1.51~g~NaCO_3=1.89~g~NaCO_3

<u>Amount of Silver Nitrate</u>

<u />

All the silver nitrate would be consumed in the reaction

I hope it helps!

<u />

<u />

<u />

7 0
4 years ago
For the following reaction, 3.70 grams of oxygen gas are mixed with excess carbon monoxide . The reaction yields 8.25 grams of c
Elden [556K]

Answer:

81% Yield

Explanation:

2CO        +               O₂                                =>     2CO₂

Excess                3.70g O₂                          =>     8.25g CO₂ (actural yield)

               (3.70g O₂)/(32g O₂/mol O₂)

                   = 0.1156 mol O₂                       =>  2(0.1156) mol CO₂

                                                                          = 10.175g (Theoretical Yield)

%Yield = (Actual Yield / Theoretical Yield)100%  

= (8.25g/10.175g)100% = 81% Yield

4 0
3 years ago
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