Answer:
B'(3, 5)
Step-by-step explanation:
Rule for the translation of a point (x, y) by 'h' units left and 'k' units upwards,
(x, y) → (x - h, y + k)
If h = 4 and k = 3,
Following this rule coordinates of the image point of B will be,
B(7, 2) → B'(7 - 4, 2 + 3)
→ B'(3, 5)
Therefore, coordinates of the image point B' will be,
B'(3, 5)
Answer:
its 5/4! haha i used to be good at this when i was in 6th grade:)
Answer:
The value of 2n - 2 is 4.
Step-by-step explanation:
Given the equation
Subtract 7 from both sides of the equation
Simplify
Now substituting n = 3 in the equation
2n - 2 = 2(3) - 2
= 6 - 2
= 4
Therefore, the value of 2n - 2 is 4.
Answer:
- y = 81-x
- the domain of P(x) is [0, 81]
- P is maximized at (x, y) = (54, 27)
Step-by-step explanation:
<u>Given</u>
- x plus y equals 81
- x and y are non-negative
<u>Find</u>
- P equals x squared y is maximized
<u>Solution</u>
a. Solve x plus y equals 81 for y.
y equals 81 minus x
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b. Substitute the result from part a into the equation P equals x squared y for the variable that is to be maximized.
P equals x squared left parenthesis 81 minus x right parenthesis
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c. Find the domain of the function P found in part b.
left bracket 0 comma 81 right bracket
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d. Find dP/dx. Solve the equation dP/dx = 0.
P = 81x² -x³
dP/dx = 162x -3x² = 3x(54 -x) = 0
The zero product rule tells us the solutions to this equation are x=0 and x=54, the values of x that make the factors be zero. x=0 is an extraneous solution for this problem so ...
P is maximized at (x, y) = (54, 27).
